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sashaice [31]
2 years ago
10

Bob Sparkle is mixing up a batch of Nuclear Fizz punch. He

Mathematics
1 answer:
jeyben [28]2 years ago
6 0

Answer:

19 oz of cranberry juice

Step-by-step explanation:

32oz of water * (3 parts juice/5 parts water) = 19.2 oz of cranberry juice

Hope this helps!

Have a nice day <3

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Does anyone know the answer to this?
Maslowich
I only found b I’m still working on a anyways.

Answer:
339

Explain: 339+39= 378 you can divide 378 by 9 which is 42, 42 subtracted by 3 is 39
3 0
3 years ago
Factor tree<br>67344 using prime numbers​
Aleksandr-060686 [28]

Answer:

2^4*3*23*61

Step-by-step explanation:

\begin{array}{c|c}67344&2\\33672&2\\16836&2\\8418&2\\4209&3\\1403&23\\61&61\\1&\\\end{array}

8 0
3 years ago
A sphere is inscribed in a cube with a volume of 64 cubic inches. What is the volume of the sphere? Round your answer to the nea
erma4kov [3.2K]

Answer:

the volume of the sphere is

33.51 in^{3}

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere and cube.

Given data

Volume of cube v =   64 cubic inches

since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,

we know that volume of cube is expressed as

v= l*b*h

v=l^{3}

64= l^{3}

l= \sqrt[3]{64}

l= 4 in

also diameter d=length l

Diameter d=  4in

Radius r =  \frac{d}{2}= \frac{4}{2}= {2 in}

Height h=4in

we know that the volume of a sphere is given by

v= \frac{4}{3} \pi r^{3}

substituting into the formula we have

v= \frac{4}{3} \ *3.142*2^{3} \\v=\frac{4*3.142*8}3} \\v= \frac{100.54}{3} \\v= 33.52in^{3}

8 0
2 years ago
I’ll give brainliest if correct
Tems11 [23]

Answer:

a

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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