X pounds of $3
y pounds of $3.25
x+y = 200
300x + 325y = 320*200
300x + 325y = 64000
x+y =200
300x +325y =64000
Solve by eliminating
Multiply top one w/-300
-300y =60000
325y=64000
25y = 4000
y= 160 then
x + 160= 200
x = 40
So the mixture has;
40 pounds of $3 coffee
160 pounds of $3.25 coffee
Answer:
19
Step-by-step explanation:
Answer:
The required expression that represents the number of pound of coffees B is 
Step-by-step explanation:
Consider the provided information.
You want to mix two coffees in order to obtain 100 pounds of a blend.
Let x represents the number of pounds of coffee A and y represents the number of pounds of coffee B.
The obtained weight is 100 pounds.


Hence, the required expression that represents the number of pound of coffees B is 
Answer:
Step-by-step explanation:
The difference in fixed cost is $9; the difference in per-mile cost is $0.02. The difference in per-mile cost will equal the difference in fixed cost for a distance of ...
$9.00/($0.02/mi) = 450 mi
At that distance, the rental cost is ...
$50 +450×$0.15 = $50 +67.50 = $117.50
Both plans will cost $117.50 for 450 miles of driving.