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madreJ [45]
3 years ago
6

Can someone pls help me? Determine the measures of the unknown angles in the figure below.

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

x= 127

w =  53

Step-by-step explanation:

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Can someone help ASAP !!
Olin [163]

Answer:

I can't help.

Step-by-step explanation:

There is no question, so therefore, I can not help.

6 0
3 years ago
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A square has side length of 5 cm. The square was changed using a scale factor of 0.6.
Aliun [14]
So the side length became 0.6*5  = 3 cm.
8 0
3 years ago
Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20
ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2,\pm\sqrt{5}

Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0

P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

       0      2     -4     -10       20

   _____________________

       1     -2      -5      10      |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

       0      2      0    -10    

    ______________

       1      0      -5     |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

8 0
3 years ago
22 = 3x - 10 and 23 = x + 30 x = [?]​
Vlad [161]

Answer:

48

Step-by-step explanation:

7 0
3 years ago
6. The heights of men selected from a particular population have a normal distribution with mean 68 inches and standard deviatio
olchik [2.2K]

Answer:

a) the proportion is 0.159 (15.9%)

b) the proportion is 0.524 (52.4%)

c) Ralph is 70.958 inches tall

Step-by-step explanation:

defining our random variable X= heights of men , then we can define the standard random variable Z as

Z= (X- μ)/σ , where  μ is the population's mean and σ is the corresponding standard deviation of X

then for X=72

Z= (X- μ)/σ

Z= (72-68)/4 = 1

a) P(X> 72) = P(Z> 1) = 1-0.841 = 0.159 (using standard normal distribution tables)

b) for X=64 and X=74

Z₁= (64 -68)/4 = -1

Z₂= (74-68)/4 = 1.5

then

P(68<X< 74) = P(-1<Z <1.5) 0 = P(Z<1.5) - P(Z<-1) =  0.933- 0.159 =0.774

c) Z₃ = 0.933 - 0.774*0.25 = 0.7395

thus

Z₃= (X₃- μ)/σ →X₃ =μ+ Z₃*σ = 68 + 0.7395*4  = 70.958 inches

therefore Ralph is 70.958 inches tall

4 0
3 years ago
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