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Anna35 [415]
3 years ago
14

If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula

for density is D. Be sure to include the correct unit. V= mL​
Chemistry
1 answer:
laila [671]3 years ago
7 0

Answer:

168.56 mL

Explanation:

density = mass/volume, use basic algebra skills to replace the volume and solve

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To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.
ZanzabumX [31]

To determine the mass of CO₂, the following must be known :

  • the molar mass of CaCO₃
  • the mole ratio of CaCO₃ to CO₂
  • the molar mass of CO₂
<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of  CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of  CaCO₃ from the molar mass of  CaCO₃

\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}

2. Find the mole ratio of  CaCO₃ : CO₂(from equation = 1 : 1)

\tt n_{CaCO_3}\div n_{CO_2}=1\div 1

3. Find the mass of CO₂ from the molar mass of CO₂

\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}

3 0
3 years ago
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Which of the following pair has a larger size? a)K or K- b)Br or Br- c)O2- or F- d) Li or Na​
Anna11 [10]

Answer:

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Explanation:

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7 0
3 years ago
Compound A and compound B are constitutional isomers with molecular formula C3H7Cl. When compound A is treated with sodium metho
mars1129 [50]

Answer:

Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.

When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.

Explanation:

Constitutional isomers are the one which differs in the structural formula.

When compound A is treated with sodium methoxide, a substitution reaction predominates.

That means sodium methoxide is a strong base and a strong nucleophile.

But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.

The reaction and the structures of A and B are shown below:

3 0
3 years ago
Use the following balanced equation to answer the questions below.
Blababa [14]

Answer:

A. 4.5 mol Mg(OH)₂

B. 6 mol NaOH

Explanation:

Let's consider the following balanced equation.

Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃

PART A

The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:

9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂

PART B

The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:

6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH

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3 years ago
Do you think it is appropriate to have diet pop available in your school?
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Answer:

I think so

Explanation:

It would provide an extra energy boost with lower sugars. Students bring drinks to school anyways so it would be nice to offer some that aren't as detrimental.

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