Answer:
The correct answer is 0.206 moles
Explanation:
According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:
Given that
Amount of 
is 11.0 grams
And, the volume is 235 mL
Now the molar mass of is 53.49g/mol
So, the number of moles presented is
= 11.0 ÷ 53.49
= 0.206 moles
hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles
The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2
so 1mole of NH3 will give 1 mole of NO2
43.9 grams of NH3 contains 2.58 moles
so 2.58 moles will be produced of NO2
which is 118.7 grams this the amount of oxygen that is used.
Answer:
0.00471 grams H₂O
Explanation:
To determine the mass, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy/heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = temperature change (°C)
The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".
Q = 0.709 J c = 4182 J/g°C
m = ? g ΔT = 0.036 °C
Q = mcΔT <----- Equation
0.709 J = m(4182 J/g°C)(0.036 °C) <----- Insert values
0.709 J = m(150.552) <----- Multiply 4182 and 0.036
0.00471 = m <----- Divide both sides by 150.552
Answer:
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<h3><u>c) 13.29 mL</u></h3>
