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olasank [31]
3 years ago
9

Write an explicit formula for an, the nth term of the sequence 2, -1, –4, ....

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

a(n) = a(1) -3(n-1)

Step-by-step explanation:

ryzh [129]3 years ago
4 0
A(n)=a(1)-3(n-1)
Step by step explanation
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Michele wanted to measure the height of her school’s flagpole. She placed a mirror on the ground 48 feet from the flagpole, then
yulyashka [42]
Height of the flagpole = x
distance from flagpole to the mirror = 48 ft
height of Michele = 5 ft
distance from Michele to the mirror = 12 ft

Now, set the proportion.

x/48 = 5/12
48 * x/48 = 5/12 * 48
x = 240/12
x = 20

So, the height of the flagpole is 20 ft.

HOPE THIS HELPS!!!!
5 0
3 years ago
Where can u place these at tell me
Alex777 [14]
The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2

Hope this helps :)
5 0
3 years ago
Please need help on this question.
Stella [2.4K]

Answer:

(4,5)

Step-by-step explanation:

8 0
3 years ago
Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1

\bar{c}=6x^{-1}+\frac{1}{6}x+k_1

6 0
3 years ago
In △EKL, m∠K = 90º, m∠E = 25º, EK = 3 cm, KH - altitude. Find EH.
laiz [17]

Answer:

EH = 3.31

Step-by-step explanation:

We have been given a right angle triangle EKL. As KH has been given as the altitude (perpendicular) of the right angled triangle, and K is the right angle, we can say that EK is tthe base of the triangle and EH is the only side lleft, which is the hypotenuse of the triangle.

Where,

EK = Base = 3

KH = perpendicular altitude

EH = Hypotenuse

m<K = 90

m<E = 25

We know that

cosθ = Base/ Hypotenuse

cos 25 = 3/ EH

EH = 3/cos25

EH = 3.31

Perpendicular alitutude can also be calculated by using the formula for tanθ.

3 0
3 years ago
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