All categories

3 years ago

How can you subtract integers in real-world situations ?

Mathematics

1 answer:

lubasha [3.4K]3 years ago

8 0

If you have a bank account and you need to withdraw into the negatives

You might be interested in

PLEASE HELP

kifflom [539]

$\\ \sf\longmapsto \dfrac{x^2-1}{x^2+5x+4}\leqslant 0$

Solving denominator

$\\ \sf\longmapsto x^2+5x+4>0$

$\\ \sf\longmapsto x^2+4x+x+4>0$

$\\ \sf\longmapsto x(x+4)+1(x+4)>0$

$\\ \sf\longmapsto (x+4)(x+1)>0$

$\\ \sf\longmapsto x>-4\:or x>-1$

Hence x $\neq$ -1
x can't be 0 as it makes function undefined

$\\ \sf\longmapsto -4$

5 0

3 years ago

What is the answer and how do you solve 21x^3/3x^−1

Sunny_sXe [5.5K]

Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

6 0

3 years ago

Find the area of this triangle

Dahasolnce [82]

A. 48 is the answer because 8x6

6 0

3 years ago

Read 2 more answers

4 divide by 2 and add 1 Input Output 0 2 -8 100

alexandr402 [8]

Answer:

Step-by-step explanation:

Given:

4 Divide by 2 and add 1

Computation;

[4 / 2] + 1

Using BODMAS rule

⇒ [4 / 2] + 1

⇒ 2 + 1

5 0

3 years ago

What is the probability of getting heads and a b, c, and d

sp2606 [1]

I mean probably of getting head is a half if that's what u mean but what is a,b,c,d

4 0

3 years ago