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Mumz [18]
3 years ago
12

How can you subtract integers in real-world situations ?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

If you have a bank account and you need to withdraw into the negatives

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Convert the following into slope-intercept form. 3x+4y=-16
Eva8 [605]

Answer:

y = -3/4x -4

Step-by-step explanation:

3x+4y=-16

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Subtract 3x from each side

3x -3x+4y=-3x-16

4y = -3x-16

Divide each side by 4

4y/4 = -3x/4 - 16/4

y = -3/4x -4

6 0
3 years ago
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A polygon is regular if each of its sides has the same length. Find the perimeter of the regular polygon. #36
vazorg [7]
Take the length of one of the sides and times that by the radius. Divide that answer by 2. Now take that and multiply by the number of sides the polygon has. If you can't find the radius or side, you're going to have to use tan, sin, or cos.
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3 years ago
Find a percent of a number by making a proportion.<br> 2 1/2% of 13.7
AleksandrR [38]

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8 0
2 years ago
Please answer correctly !!!!!!!! Will mark brianliest !!!!!!!!!!!
nexus9112 [7]

Answer:

x=6

Step-by-step explanation:

h(x) = -( x-2)^2 +16

We want when h(x) = 0

0 = -( x-2)^2 +16

Subtract 16 from each side

-16  = -( x-2)^2 +16-16

-16 = -( x-2)^2

Divide by -1

16= ( x-2)^2

Take the square root of each side

±sqrt(16) = sqrt(( x-2)^2 )

±4 = x-2

Add 2 to each sdie

2 ±4 = x-2+2

2+4 = x     2-4 =x

6 =x           -2 =x

since time cannot be negative

x=6

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3 years ago
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Answer is in the file
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