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3 years ago

What does conserving mass mean in a chemical equation?

2 answers:

5 0

I have the same quiz! The answer is C. There is an equal number of each atom on the reactant and product side. I hope this helps! :)

Keith_Richards [23]3 years ago

4 0

The answer would be C. Hope this helps

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What is the product of every combustion reaction

Stolb23 [73]

Answer:

The products of combustion reactions are compounds of oxygen, called oxides.

Explanation:

5 0

3 years ago

Calculate the percentage by mass of the indicated element in the following compounds.

jarptica [38.1K]

Answer: The mass percent of carbon in acetylene is 92.31 %.

Explanation:

In $C_2H_2$ , there are 2 carbon atoms and 2 hydrogen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of carbon}=\frac{\text{Mass of carbon}}{\text{Molar mass of acetylene}}\times 100$

Mass of carbon = $2\times 12g/mol=24g$

Mass of acetylene = $2\times 12g/mol+2\times 1g/mol=26g$

Putting values in above equation, we get:-

$\text{Mass percent of carbon}=\frac{24}{26}\times 100=92.31\%$

Hence, the mass percent of carbon in acetylene is 92.31 %.

7 0

3 years ago

How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions

omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$

$Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V$

The substance having highest positive reduction $E^o$ potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

$Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V$ ..[1]

Oxidation: anode

$Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V$ ..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

$E^o_{cell}=-0.036V-(-2.37 V)=2.334 V$

The overall reaction will be:

2 × [1] + 3 × [2] :

$2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-$

Electrons on both sides will get cancelled :

$2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)$

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

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4 years ago

Ch at me on dis cord if u want a friend or just wanna talk<br> . <br><br> Kgirl633#5722

sp2606 [1]

Answer:

Explanation:

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3 years ago

01:54:24

max2010maxim [7]

Answer:

[C]

Explanation: -Cause i took the test on engenuity

8 0

3 years ago