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3 years ago

How many oxygen atoms are in 10.0g of 2Al2 CO3 3

Chemistry

1 answer:

LekaFEV [45]3 years ago

5 0

Answer:

0.776 ×10²³ atoms of oxygen

Explanation:

Given data:

Mass of Al₂CO₃ = 10.0 g

Number of atoms of oxygen = ?

Solution:

Number of moles of Al₂CO₃:

Number of moles = mass/molar mass

Number of moles = 10.0 g/233.99 g/mol

Number of moles = 0.043 mol

1 mole of Al₂CO₃ contain 3 mole of oxygen.

0.043 ×3 mol = 0.129 mol

Number of atoms of oxygen:

1 mole contain 6.022×10²³ atoms

0.129 mol × 6.022×10²³ atoms / 1mol

0.776 ×10²³ atoms of oxygen

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Answer:

Explanation:

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Wich value gives the number of particles in 1 mol of a substance

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Density of cold water = 1 g/mL

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Density of hot water = 1 g/mL

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$1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g$

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where,

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$m_2$ = mass of cold water = 230 g

$T_{final}$ = final temperature = ?°C

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$T_2$ = initial temperature of cold water = 25°C

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Putting values in equation 1, we get:

$120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]$

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