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zlopas [31]
3 years ago
5

What is the mass of 7.1 x 1021 molecules of glucose?

Chemistry
1 answer:
choli [55]3 years ago
7 0

Answer:

7249.1

Explanation:

Multiply 7.1x1021= 7249.1

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Use the helium-4 isotope to define atomic number and mass number. why does knowledge of atomic number enable us to deduce the nu
Nuetrik [128]
Helium - 4 isotope has 2 protons and 2 neutrons.

Its atomic number is 2 (the number of protons). Atomic number is the number of protons in the atom of an element and it identifies the element. All the isotopes of an element have the same atomic number (same number of protons). So, all the isotopes of hellium have 2 protons.

The number 4 that identifies the helium - 4 isotope is the mass number, i.e. the number of protons plus the number of neutron. So, helium-4 isotope has 2 protons and 2 neutrons. While, other isotopes of helium have 2 protons but different number of neutrons.

The atomic number enable us to deduce the number of electrons in an atom because the atoms are neutral, which implies that the positive and negative charge are equal. Given that the magnitude of the charge of electons and protons are equal but the sign is opposed (protons are positve and electrons are negative) the number of electrons in the atom equals the number of protonts. That is why the atomic number is also the number of electrons of the atom.
8 0
4 years ago
Which is heavier Calcium (Ca) or Silicon (Si)
ki77a [65]

Answer:

Calcium is heavier a little bit

3 0
4 years ago
997.62 mol = 56.367 L<br> =
Galina-37 [17]
14.626 Gallons because yeah dhhsjsjshshsh
4 0
3 years ago
The decomposition of N I 3 to form N 2 and I 2 releases − 290.0 kJ of energy. The reaction can be represented as 2N I 3 (s)→ N 2
ella [17]

Answer:

The change in enthaply when 10.0 g of nitrogen triiodide decomposes is -3.67 kJ.

Explanation:

2NI_3 (s)\rightarrow N_2 (g)+3 I_2 (g), \Delta H_{rxn} =-290.0 kJ

Enthalpy of the reaction when 2 moles of nitrogen triiodide decomposed =\Delta H_{rxn}

\Delta H_{rxn} = -290.0 kJ

Enthalpy of the reaction when 1 moles of nitrogen triiodide decomposed :

\Delta H=\frac{\Delta H_{rxn}}{2}=\frac{-290.0 kJ}{2} =-145.0 kJ

Mass of nitrogen triiodide decomposed = 10.0 g

Moles of nitrogen triiodide = \frac{10.0 g}{395 g/mol}=0.02532 mol

Change in enthaply when 0.02532 moles of nitrogen triiodide decomposed:

\Delta H\times 0.02532=-145 kJ\times 0.02532=-3.67 kJ

3 0
3 years ago
In the chamber below, the volume is 20.5 L. What would the volume be if the temperature is increased to 500 K, the moles are red
grandymaker [24]

Answer:

C. bc I ssid

Explanation:

0+0+0+0+0+0=00

3 0
3 years ago
Read 2 more answers
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