1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
butalik [34]
3 years ago
13

1/2(4y + 18) + 2 simplified

Mathematics
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer: 2y+11

Step-by-step explanation:

I hope this helps<3

You might be interested in
9(3+c+4) what is the answer
zzz [600]

Answer:

the answer is 9c+63

Step-by-step explanation:

4 0
3 years ago
* please explain work / show it thxsss!!**
serious [3.7K]

Answer:

All you need to do is to calculate the perimeter of the circle since you already had the diameter

Base on the picture, the perimeter should be:

C = d * π = 64 * 3.14 = 200.96 (m)

8 0
3 years ago
Find the Volume. help please ​
Oksana_A [137]
104 1/2ft cubed
To find the volume you would multiply
Length•width•height
So,
(6 1/3)(3)(5 1/2)=104 1/2
So it would be 104 and 1/2 or 104.5
6 0
3 years ago
Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin
ozzi

I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta  \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt

by using the integration formula

we get,

\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c

now put the value of t=\sin\theta in the above equation

we get,

\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c

hence proved

7 0
3 years ago
A stadium has 45,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. If section C held 300 fewer
White raven [17]

Answer:

Let's define the variables:

A = number of seats in section A.

B = number of seats in section B.

C = number of seats in section C.

We have the equations:

A + B + C = 45,000.

C - 300 = B/2

A*$28 + B*$24 + C*$20 = $1,139,200

This is a system of equations, the first step to solve this is to isolate one variable in one of the equations, and then replace it in the others.

I will isolate C in the second equation:

C = B/2 + 300.

Now let's replace this in the other two equations:

A + B + B/2 + 300 = 45,000

A*$28 + B*$24 + (B/2 + 300)*$20 = $1,139,200

Let's simplify these equations:

A + B*(3/2) = 44,700

A*$28 + B*$34 + $6,000 = $1,139,200

Now let's isolate A in the first equation:

A = 44,700 - B*(3/2)

Let's replace this in the other equation:

(44,700 - B*(3/2))*$28 + B*$34 + $6,000 = $1,139,200

Now let's solve this for B.

-B*$8 + $1,252,200 = $1,139,200

-B*$8 =  $1,139,200 - $1,252,200  = -$113,000

B = $113,000/8 = 14,125

Now we can replace that in the equations:

A =  44,700 - B*(3/2) =  44,700 - 14,125*(3/2) = 23,512.5, that we should round up to 23,513.

And C = B/2 + 300 = 7362.5

As we rounded the previous one up, we should round this one down to 7362.

3 0
3 years ago
Other questions:
  • Compare 7/21 and 3/18 using &gt; &lt; or =
    8·1 answer
  • How to slove this problem?
    11·2 answers
  • A jacket usually sells for $69.00. If the jacket is 30% off, and sales tax is 8%, what is the total price of the jacket, includi
    10·1 answer
  • What is 805 ten equal to
    6·1 answer
  • PLEASE HELPPPPPPPPPPPPPP THANK YOUUH
    14·1 answer
  • Rectangle a is dilated to form rectangle b. what is the scale factor used .​
    6·1 answer
  • What fraction is the same as 10x1/2
    9·2 answers
  • Please help, I’ll mark you as brainliest!!:)
    14·2 answers
  • Unit test
    11·1 answer
  • Given f(x) = (lnx)^3 find the line tangent to f at x = 3
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!