Question

At a particular pressure and temperature, nitrogen gas effuses at the rate of 79 mL/s. Under the same conditions, at what rate will sulfur dioxide effuse?

Answer 1

Rate of Sulfur dioxide : 2730.44 mL/s

Further explanation  

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

or  

$\rm M_1\times r_1^2=M_2\times r_2^2$

MW of N₂ = 28 g/mol

MW SO₂ = 64 g/mol

$\tt 28\times 79^2=64\times r_2^2\\\\r_2^2=\dfrac{28\times 79^2}{64}=2730.44~mL/s$