In this question, you are given the density (2.7g/ml) and the volume of the aluminum. You are asked how much the volume is. To answer this question, you need to convert the volume into mass. Since the unit used is already same, you don't need to convert it into another unit. The calculation would be:
mass= volume / density
mass= 405ml / (2.70 g/ml)
mass= 150grams
Answer:
<u>Question</u><u> </u><u>1</u><u> </u><u>:</u>
• A compound is ionic if it is made up of a metal or a cation (+) and a non metal or anion (-)
<u>Question</u><u> </u><u>2</u><u> </u><u>:</u>
• While naming ionic compounds, follow the formula → "metal" + "non-metal ending with <em>ide</em><em> </em>"
• i.e; Sodium Chloride:

<u>Question</u><u> </u><u>3</u><u> </u><u>:</u>
• The answer above that question is perfect.
<u>Question</u><u> </u><u>4</u><u> </u><u>:</u>
1 atom → Mono. But it is highly recommended to ignore it
2 atoms → DI
3 atoms → TRI
4 atoms → TETRA
5 atoms → PENTA ( such as pentaoxide )
7 atoms → HEPTA ( such as heptaoxide )
<u>Question</u><u> </u><u>5</u><u> </u><u>and</u><u> </u><u>6</u><u>:</u>
Are perfectly answered.
The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is <span>Group 17, Period 2.</span>
Answer:
![AU^{3+} : [Rn] 5f^3](https://tex.z-dn.net/?f=AU%5E%7B3%2B%7D%20%3A%20%5BRn%5D%205f%5E3)
Explanation:
Writing electronic configuration of any element you should know atomic number of that element ,
and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital
and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.
writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.
![AU : [Rn] 5f^3 6d^1 7s^2](https://tex.z-dn.net/?f=AU%20%3A%20%5BRn%5D%205f%5E3%206d%5E1%207s%5E2)
remove three electron from outer most shell of AU
![AU^{3+} : [Rn] 5f^3](https://tex.z-dn.net/?f=AU%5E%7B3%2B%7D%20%3A%20%5BRn%5D%205f%5E3)