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vaieri [72.5K]
3 years ago
7

The length of the titanic was 882 feet. Porter's history class is building a model if th titanic. The model is 1

Mathematics
2 answers:
Artemon [7]3 years ago
6 0
The model size would be 8.82 feet I think
mojhsa [17]3 years ago
3 0
The model size would be 8.82 because 882 divided by 100 is 8.82
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Can someone please answer this for me I'm begging
GrogVix [38]
If the length of JK is 16.4 miles, it will be diameter of this circle, the radius will be JK/2 = 8.2 miles

As we know the length of circle is 2π*r  in this case r = 8.2

The arc JM is 1/4 length of the whole circle so arc JM = (2π*8.2)*(1/4) = 2π*8.2/4 = π*8.2/2 = π*4.1

if we assume that π=3.14 the answer will be 3.14 * 4.1 = 12.874.... And as the answer needs to be rounded to the nearest tenth it will be 12.874≈12.9

So the answer will be 12.9
8 0
3 years ago
Please help its due in 1 hour it would be best if you show work
aleksley [76]

Answer:

1:quadrant 1

2:quadrant 1

3:quadrant 2

4:quadrant 3

5:quadrant 1

6:quadrant 4

7:Z and quadrant 2

8: F and quadrant 1

9:A and quadrant 4

10: R and quadrant 4

11: N and quadrant 2

12: Q and quadrant 3

13a:the clock

13b:wonder wheel

13c:big coaster

13d: -1,2

Good luck

6 0
2 years ago
Look at the diagram.
azamat

Answer:

Option G

Step-by-step explanation:

Option F

m∠1 + 121 = 180 [Sum of linear angles = 180°]

True.

Option G

121 + m∠2 + 33 = 180

False. Because 121° is not an interior angle of the given triangle.

Option H

33 + m∠1 = 92

True.

Measure of exterior angle of a triangle is equal to the sum of he measure of the non adjacent interior angles.

Option J

121 + 92 + m∠3 = 360°

True.

Sum of the exterior angles of triangle is 180°.

5 0
2 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
Help for just 50 points!
liraira [26]

Answer:

It may be 9

Step-by-step explanation:

Solution:

Here,

Median = n+1/2th term

=5+1/2 th term

=6/2 th term

=3rd term

Now,

Arranging the data in ascending order...

  • 6,8,9,10,12

Since, 9 is the third term. So, 9 is the median.....

8 0
2 years ago
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