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3 years ago

Can someone plz help me with this it’s due rn

Mathematics

1 answer:

Rama09 [41]3 years ago

8 0

20, 20, 20, 30, 20
Tip for rounding nearest 10th: if the 2nd number is above 5 it’s the one above, if it’s below 5 it’s the one below.

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Y=x???need answers and an explanation

Lesechka [4]

Y= 2
every time y goes up it goes up by 2

-1+2=1
1+2=3
3+2=5

5 0

3 years ago

Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triang

Ymorist [56]

the coordinates of the points of intersection of the graph of y=13−x with the axes

Given equation is y=13-x

x axis is x=0

y axis is y=0

Plug in the value of x =0 and find out y

y = 13 - x

y = 13 - 0 = 13

Plug in the value of y=0 and find out x

0 = 13 - x

x= 13

So coordinate axis

x= (13,0)

y= (0,13)

Base of the triangle is x=13

Height of the triangle is y= 13

Area of the triangle = $\frac{1}{2} * base * height$

= $\frac{1}{2} * 13 * 13$ = 84.5

Area of the triangle = 84.5

6 0

3 years ago

Evaluate the radical.<br><br> 1000−−−−√3

scoray [572]

( 1000 )^1/3
= ( 10 ^3 )^ 1/3

= ( 10 ) ^ 3 × 1/3

= 10

I hope this will useful to you.

6 0

3 years ago

What is the mean of the following data values? 53,71,89,10,87

enot [183]

Answer:

Step-by-step explanation:

Mean=Sum of all values/number of observation

=53+71+89+10+87/5

=310/5

=62

7 0

3 years ago

Without using a calculator, match each expression to the correct point.

solniwko [45]

Answer:

The locations of each irrational number are the following:

$\sqrt{16}$ - Point $a$

$\sqrt{27}$ - Point $b$

$\sqrt{32}$ - Point $c$

Step-by-step explanation:

$\sqrt{16}$ is an irrational number that is also rational, since $4^{2} = 16$ . Then, $\sqrt{16}$ must be point $a$ .

Both $\sqrt{27}$ and $\sqrt{32}$ are greater than $\sqrt{25} = 5$ and less than $\sqrt{36} = 6$ . Then, both are between 5 and 6. Since $\sqrt{27} < \sqrt{32}$ , $\sqrt{27}$ must be point $b$ and $\sqrt{32}$ must be point $c$ .

3 0

3 years ago