Bro pls hlep me with #3 and #4
1 answer:
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Answer:
Area of the shaded region = 1.92 cm²
Step-by-step explanation:
From the picture attached,
Area of the shaded region = Area of the sector OMN - Area of the triangle OMN
Area of sector OMN =
Here, θ = Central angle of the sector
r = radius of the sector
Area of sector OMN =
= 15.708 square cm
Area of ΔOMN = 2(ΔOPN)
Area of ΔOPN =
Area of ΔOMN = OP × PN
In ΔOPN,
sin(25°) =
PN = ONsin(25°)
= 6sin(25°)
= 2.536 cm²
cos(25°) =
OP = ONcos(25°)
OP = 6cos(25°)
OP = 5.438 cm
Area of ΔOMN = 2.536 × 5.438
= 13.791 cm²
Area of the shaded region = 15.708 - 13.791 = 1.917 cm²
≈ 1.92 cm²
