Ask question

Ask question

All categories

3 years ago

11

Select expression that is equivalent to the one below

2 answers:

Katena32 [7]3 years ago

8 0

The answer is B
-13x and 5x combine to get -8x
-4 and -2 combine to get -6

mihalych1998 [28]3 years ago

3 0

A. 2(4x-4)= 8x-8 false❌
B. -4-2+5x-13x = -6-8x = -8x-6 true✅
C. -11x+2+3x-4 = -8x-2 false❌
D. 6-7x+x = 6-6x false❌

correct answer B
hope this helps

You might be interested in

Catherine went on a trip to the Everglades. She spent 1/3 of her time exploring the swamp and 2/3 of the remaining time bird-wat

valentinak56 [21]

54 minutes 1/3 *2 =54

3 0

4 years ago

Josh likes to read. He read 6 books when he was 6 years old. Every year he doubled the number of books he read the previous year

velikii [3]

At age 6, he read six. That doubled would be 12 books. So at age 7, he read 12. 12 doubled is 24. At age 8, he read 24. That doubled would be 48. At age 9, he read 48. That double would be 96. So by age 10, he would have read 96 books.

8 0

3 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago

blondinia [14]

Answer:

30

Step-by-step explanation:

20+2((3)(7)−(4)(4))

=20+2(21−(4)(4))

=20+2(21−16)

=20+(2)(5)

=20+10

=30

6 0

4 years ago

What is the surface area of the square-based pyramid?<br> 4.5 cm<br> 4 cm

ExtremeBDS [4]

8.5 cm I’m guessing so pls if I’m wrong I’m rlly Srry :(

7 0

3 years ago