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hammer [34]
3 years ago
15

An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.

Physics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

Force of kinetic friction, Fk = 6N

Explanation:

Given the following data;

Coefficient of kinetic friction, μ = 0.2

Normal force, Fn=30N

To find the Force of kinetic friction;

Mathematically, the force of kinetic friction is given by the formula;

Fk = μFn

Where;

  • Fk represents the force of kinetic friction.
  • μ represents the coefficient of friction.
  • Fn represents the normal force.

Substituting into the equation, we have;

Fk = 0.2*30

Fk = 6N

Therefore, the force of kinetic friction is 6N.

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An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m
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Answer:

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4 years ago
A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to
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When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

<h3>Frictional force between the block and the horizontal surface</h3>

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

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When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

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Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Learn more about frictional force here: brainly.com/question/4618599

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<u>Answers:</u>

<em><u>The </u></em><em><u>gravitational</u></em><em><u> potential</u></em><em><u> energy</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>diver </u></em><em><u>when </u></em><em><u>he</u></em><em><u> reaches</u></em><em><u> point</u></em><em><u> C</u></em><em><u> </u></em><em><u>is </u></em><em><u>4</u></em><em><u>4</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>J.</u></em>

<em><u>The </u></em><em><u>velocity</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>diver </u></em><em><u>is </u></em><em><u>9</u></em><em><u>.</u></em><em><u>9</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0
2 years ago
Read 2 more answers
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