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Crazy boy [7]
2 years ago
14

Help me help me pls............

Mathematics
2 answers:
MariettaO [177]2 years ago
5 0

Answer:

You're Question is hard¯

attashe74 [19]2 years ago
3 0

Answer:

2

sorry i dont know but i think the answer is 2 I am not sure dont bleve me

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Three ways to write 3 to the 5th power
cestrela7 [59]

First expression

=>  3 x  3 x  3 x 3 x 3 – In this expression, we multiplied 3 5 times and the product is 243

Second expression

=> 3 ^ 5 , in where ^ read as raised to the power. , the product is also 243

Third expression

=> 3^2 x 3 ^3

=> (3 x 3) x (3 x 3 x 3)

=> 9 x 27, the product is also equals to 243.

7 0
2 years ago
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Convert 8/15 into a decimal : show your work
zloy xaker [14]
O.533333333,basically 8 divide by 15
6 0
3 years ago
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Plz help me 1+2p+9p-4
Charra [1.4K]
-3+11p
first you add 1+2p that gets you -3 then you do 9p-4 and you get 11p from there you can either solve it, or leave it as is, depending on what your teacher wants.
8 0
3 years ago
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If anyone understands this one
Murrr4er [49]
The answer is C, the commutative property of multiplication.
6 0
2 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
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