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3 years ago

Help me help me pls............

Mathematics

2 answers:

MariettaO [177]3 years ago

5 0

Answer:

You're Question is hard¯

attashe74 [19]3 years ago

3 0

Answer:

sorry i dont know but i think the answer is 2 I am not sure dont bleve me

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Y = 3x x + y = 52 substitution method help quick show all work

AfilCa [17]

Answer:

$x + 3x = 52 \\ 4x = 52 \\ x = 13 \\ y = 3x = 3 \times 13 = 39$

8 0

3 years ago

If log10 C = y, then what does c equal?

Zigmanuir [339]

Answer:

$C = 10^y$

Step-by-step explanation:

By the definition of a log, $C = 10^y$

4 0

3 years ago

A 15% discount saves you $5 off the price of an electric game how much do you save off the regular price of the discount is Rave

xenn [34]

You will save $15
x×0.15=5
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x×0.45=15

8 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Victor made a cake for his cousin's birthday party. Victor baked the cake for 40 minutes. It took 8 times as long for Victor to

irga5000 [103]

Answer:

320 min. or 5 hrs 20 min.

Step-by-step explanation:

40 x 8 = 320

6 0

3 years ago