It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
Answer:
![x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=x%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Step-by-step explanation:
you have the following formula:
To solve this equation you use the following properties:
Thne, by using this propwerty in the equation (1) you obtain for x
![log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=log_%7B%28%5Cfrac%7B1%7D%7B81%7D%29%7D%28%5Cfrac%7B1%7D%7B81%7D%29%5E%7B%5Cfrac%7Bx%7D%7B243%7D%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B243%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5Cx%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Answer:
She needs to sell for 64 more hours
Step-by-step explanation:
Answer:
A. Starting at the origin, go 3.5 spaces to the right and then 4 spaces up.
Step-by-step explanation:
if you were to plot this then the point would be (3.5,4) instead of (4,3.5)
The answer to the question
