If a block of copper is 5 cm by 10 cm by 3 cm and has a mass of 1335 grams, what is the density of copper?

Mathematics

2 answers:

vodomira [7]3 years ago

7 0

Answer:

The answer is 8.9 gm/cm cubed

Step-by-step explanation:

Just did it on algebra nation

Maslowich3 years ago

5 0

Answer:

the density of copper is 90.03g/cm³

Step-by-step explanation:

This problem bothers on the density of a substance, this case for a copper material

Given data

Mass of copper m = 1355g

Volume of copper block v= l*b*h

10*5*3=150cm³

We know that the density

ρ= mass/volume

ρ= 1355/150

ρ= 90.03g/cm²

The density of a substance is defined as the mass of the substance per unit volume

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Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

beks73 [17]

You can check that the limit comes in an undefined form:

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and

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6 0

2 years ago

1.Simplify 5 to the 5th over 5 to the 8th.

timurjin [86]

Q1. The answer is 1 over 5 to the 3rd power.

5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is $\frac{ 5^{5} }{ 5^{8} }$
To simplify, we will use two rules:
$\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}$
Therefore:
$\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}$
$\frac{1}{5^{3}}$ is the same as 1 over 5 to the 3rd power.

Q2. The answer is (53)−4.

The exponents are multiplied when are expressed in the form:
 $(x^{a}) ^{b}= x^{a*b}$
So, $(5^{3} )^{-4}=5^{3*(-4)}=5^{-12}$

Other choices are incorrect:
one third to the 4th times one third to the 7th is $( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}$
3 to the 7th over 3 to the 15th is $\frac{ 3^{7} }{3^{15}} =3^{7-15}$
45 ⋅ 42 is $4^{5}* 4^{2} = 4^{5+2}$