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antiseptic1488 [7]
3 years ago
6

What is the slope-intercept equation for this line(y= mx + b)? ​

Mathematics
2 answers:
icang [17]3 years ago
7 0

Answer: y = -6x +2

Step-by-step explanation:

rise/run is 6/1 so slope = 6

y intercept of 2

lbvjy [14]3 years ago
4 0

Answer:

y = -6x + 2

Step-by-step explanation:

To find the slope, you do rise/run. To get to one point from another, you move one unit to the right, and six units down.

Now to find the y-intercept, you need to identify the point that meets in the y-axis. That would be 2.

Hope this helps!

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What's the answer to 1/2(x+4)^2-5+=3.
nadya68 [22]

Answer:

x = 0

Step-by-step explanation:

To solve this equation you would need to get x by itself on one side

1/2 (x+4)^2 - 5 = 3

1.) add 5 to both sides

1/2 (x+4)^2 = 8

2.) divide each side by 1/2

(x+4)^2 = 16

3.) find the square root of both sides

(x+4) = 4

4.) subtract 4 from both sides

x = 0

The app "Photomath" is a great way to solve problems like these and it gives a step by step explanation that might be easier to understand than mine :)

6 0
3 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
Plz help due tonight
rusak2 [61]

Answer:

The bottom left square of the triangle in 90 degrees always so take 90 + 40 giving you 130,

a Triangle has 180 degrees in total so 180 -130 = 50 degrees for the last side

5 0
2 years ago
Read 2 more answers
3. What is the equation in slope-intercept form of the line that passes through the
zavuch27 [327]
The Answer: y=1/4x+3
3 0
3 years ago
7/6 divided by 2 in simplest form
iris [78.8K]
Here is your question: 7/6 divided by 2.

= 7/6÷2 = 7/6 * 1/2 =.

Multiply and you get = 7/12.
6 0
3 years ago
Read 2 more answers
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