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3 years ago

Find the slope of the line. 11 10 2 7 8 910 The slope is

Mathematics

1 answer:

ANEK [815]3 years ago

6 0

Answer:

Step-by-step explanation:

where is the graph first?

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What is the area of a square with a side length of 10cm?

natita [175]

Answer:

100cm

Step-by-step explanation:

10*10

4 0

3 years ago

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What is 6,000 people voted in the election how many were from 18 to 29 years old?

Ilia_Sergeevich [38]

6000*10%=600
600 people voted at at aged 18 to 29 years old.

4 0

3 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago

Find the area of rectangles with the following dimensions.

seraphim [82]

Answer:

I think this is the answer I hope I have helped you

Step-by-step explanation:

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3 years ago

According to Statcast, the average left field home run travels 378 feet and reaches a maximum height of 81 feet. Assuming the ba

kogti [31]

Answer:

H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)

If H is to be considered an absolute value from t = 0

h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground

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3 years ago