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3 years ago

Which scatterplot shows a negative correlation?

Mathematics

1 answer:

Setler79 [48]3 years ago

8 0

Answer:

Plot B

Step-by-step explanation:

Plot B has a negative slope.

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serg [7]

Based on what I know it’s B because the others have exponents and linear functions don’t have exponents

8 0

3 years ago

Find the measure of angle x

Nikitich [7]

x = 90 - 28

x = 62°

The answer is choice B.

4 0

3 years ago

Read 2 more answers

Linear equation: -1

Anika [276]

Answer:

The right answer is:

the addition property of equality and then the division property of equality

Step-by-step explanation:

Given equation and steps to solve it are:

Step 1: –3x – 5 = 13

Step 2: –3x = 18

Step 3: x = –6

In step two, -5 has to be removed from left hand side of the equation so additional property of equality will be used i.e. adding 5 on both sides

Similarly in the third step, to remove -3 with x , division property of equality will be used i.e. dividing both sides by -3

Hence,

The right answer is:

the addition property of equality and then the division property of equality

6 0

3 years ago

Read 2 more answers

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers

Can the sides of a triangle have lengths 1, 7, and 11? Explain

Airida [17]

Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.

Consider the 3 given sides 1, 7 and 11

7 + 11 = 18 > 1

1 + 11 = 12 > 7

1 + 7 < 11 ⇒ not valid

Hence these sides do not form a triangle

6 0

3 years ago