All categories

3 years ago

Factors of (1-x^2) answer fast please

Mathematics

1 answer:

MatroZZZ [7]3 years ago

5 0

Answer:

(−x−1)(x−1) or 1−x^2

Step-by-step explanation:

(1-x^2)

Rewrite 1-x^2 as 1^2-x^2. The difference of squares can be factored using the rule: a^2

−b^2=(a−b)(a+b).

(1−x)(1+x)

Reorder the terms.

(−x+1)(x+1)

You might be interested in

64,000 in<br> a fraction

earnstyle [38]

Answer:

undefined

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the quotient: (x2−5x+8)÷(x+2)

Aneli [31]

Answer:

Quotient = x - 7

Step-by-step explanation:

We are dividing x^2 - 5x +8 by x + 2

x + 2√x^2 - 5x + 8

Starting with dividing by x

x - 7

x + 2√ x^2 - 5x + 8

Multiplying x by x + 2

x + 2√ x^2 - 5x + 8

x^2 + 2x

= -7x + 8

Step ii, pick -7 for division

-7x + 8

-7x - 14

= +8 -(-14)

= 8+14

= 22

The answer is

( x - 7) remainder 22

(x - 7) is the quointent

22 is the remainder

3 0

3 years ago

Brendan spent 24 minutes playing a computer game. He stopped playing at 3:55 pm and went outside to ride his bike.What time did

Ivanshal [37]

What is 3:55 minus 24?

7 0

3 years ago

Read 2 more answers

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

3 years ago

Two trains leave the station at the same time, one heading west and the other east. The westbound train travels 14 miles per hou

Sergeu [11.5K]

Answer:

The answer to your question is 166 mi/h

Step-by-step explanation:

Data

ve = rate eastbound train

vw = rate westbound train = ve - 14

distance = d = 900 mi

time = t = 5 h

Formula

v = $\frac{distance}{time} = \frac{d}{t}$

Substitution and simplification

$ve = \frac{900}{5} = 180 mi/h$

Now, substitute this value in the equation of vw

vw = 180 - 14

Result

vw = 166 mi/h

7 0

3 years ago

Factors of (1-x^2) answer fast please ​

Factors of (1-x^2) answer fast please