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Serga [27]
3 years ago
6

11. How many elements do all the "P" orbital span (go across) in each period? (circle your answer)

Chemistry
1 answer:
bulgar [2K]3 years ago
8 0

Answer: B

can u pls give me brain list?

You might be interested in
8. Determine the number of significant figures in the following numbers
sweet [91]

Answer:

a) 5

b) 4

c) 3

d) 3

e) 4

Explanation:

I use only one rule when the decimal is present, meaning you can see the decimal (as is the case with all of these).

When the decimal is Present, start counting sig figs from the Pacific (left) side of the number beginning with the first non-zero digit and count all the way to the end.

So, for example, in "a", the first non-zero digit starting from the left is 1, then continue counting all the way to the right side.

For "c",  the first non-zero digit is the left most 4 (skip the first 4 zeros), then count all the way to the right side.

6 0
4 years ago
carbon-carbon covalent bonds, such as the ones in carbohydrates and lipids, are _____ and have _____.
NARA [144]

Answer:

Weak; a lot of potential energy.

Explanation:

6 0
3 years ago
Help me with this plz
Roman55 [17]

Answer:

EVEN DOE IT TOO LATE, ITS B

Explanation:

8 0
2 years ago
What are the best titles a and b A science b pseudoscience
Mars2501 [29]

i don't really know what you are trying to say here, but what i think you are saying is what sounds like a more impressive job?? in my opinion, pseudoscience sounds more fancy and interesting. Since not a lot of people really knows what that is, it sparks conversation.

8 0
3 years ago
What is the maximum number of electrons in the following energy level? n = 3
11Alexandr11 [23.1K]
Answer is: 18 electrons.

<span>The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number (l) is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital, l = 0....n-1.</span>

<span>For n = 3, l = 0, 1, 2.</span>

<span>l = 0, s orbital with 2 electron.</span>

<span>l = 1, p orbitals with 6 electrons.</span>

<span>l = 2, d orbitals with 10 electrons.</span>

<span>2 + 6 + 10 = 18 electrons.</span>


8 0
4 years ago
Read 2 more answers
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