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Ket [755]
3 years ago
11

Will mark brainliest for who is right

Chemistry
1 answer:
alina1380 [7]3 years ago
6 0
Chemical properties
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Ascorbic acid, or vitamin C (C6H8O6, molar mass = 176 g/mol), is a naturally occurring organic compound with antioxidant propert
Rus_ich [418]

Answer:

The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.

Explanation:

To determine the mass of ascorbic acid knowing the number of moles we use the following formula:

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of ascorbic acid = 2.82 × 10⁻⁴ × 176

mass of ascorbic acid = 496 × 10⁻⁴ g = 0.0496 g = 49.6 mg

daily requirement of ascorbic acid = 70 - 90 mg

The quantity of ascorbic acid found in sweet lime of 49.6 mg does not meet the daily requirement.

6 0
4 years ago
Read 2 more answers
0.5 kg or 0.5 lb which is a larger quantity
masha68 [24]
The correct answer is 0.5 kg If you whant me to explaine pls tell me
3 0
3 years ago
What is a control group?
Arte-miy333 [17]

Answer:

A control group is someone who takes control over something so a tyrant or a dictator.

Explanation:

If this isnt what your looking for let me know, there wasnt alot of context.

8 0
3 years ago
Read 2 more answers
Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
3 years ago
An atom of gold has a mass of 3.271 x 10-22g. How many atoms of gold are in 5.00g of gold?
rosijanka [135]
To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation  \frac{mass of gold}{mass of gold atom}. 

Let x be the number of gold atoms. Plug in the values to a calculator.

x = \frac{5.00g}{3.271 x 10-22g}
Both have the same units so the unit gram(g) can be cancelled. 
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
3 0
4 years ago
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