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2 years ago

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Please help me thank you!

1 answer:

Romashka [77]2 years ago

7 0

Answer:

the answer is 1¢26 if not try h5

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PLEAsE HELP[<br> simplify:<br> (3x^4y^4)(5x^4) / 20xy^2

almond37 [142]

Answer:

$\frac{3x^6y^2}{4}$

Step-by-step explanation:

$\frac{3x^6y^2}{4}$

3 0

3 years ago

a flower bed is in the shape of a triangle with one side twice the length of the shortest side and the third side is 19 feet mor

Neporo4naja [7]

Let's assume

shorter side as x

so, first side =2x

third side =x+19

now, we can find perimeter of triangle

perimeter of any triangle is

first side + shortest side + third side

so, we get

$P=2x+x+x+19$

we are given perimeter=187

so, we can set it to 187

and then solve for x

$187=2x+x+x+19$

$187=4x+19$

$4x+19-19=187-19$

$4x=168$

$x=42$

so,

shortest length is x=42 feet

First side =2x=2*42=84feet

third side =x+19=42+19=61 feet

so, dimensions are

first side is 42 feet

second side is 84 feet

third side is 61 feet................Answer

3 0

3 years ago

Jessica is baking a cake. The recipe says that she has to mix 96 grams of sugar to the flour. Jessica knows that 1 cup of this p

zepelin [54]

we are given the recipe of the cake made by Jessica. In this recipe, a cup weighs 128 grams in which the cake needs 96 grams. she uses half a cup which is equal to 64 grams. This means she needs to add 32 grams more which is 1/4 of a cup. In all, she needs 3/4 of a cup

6 0

3 years ago

Read 2 more answers

Jane is 14 years older than mary. in five years jane will be one less than twice mary's age. what is the sum of jane and mary's

Elenna [48]

Answer =44. Hope this answer is helpful and correct.

4 0

3 years ago

Let u = (1, k) and v = (2, 1). Find k such that The distance between u and v is 1 u and v are orthogonal The angle between u and

SVETLANKA909090 [29]

Answer:k=1,k=-2,k= $8\pm 5\sqrt{3}$

Step-by-step explanation:

Given two vectors

$u=1\hat{i}+k\hat{j}$

$v=2\hat{i}+1\hat{j}$

$\left ( i\right )$ Distance between them is given by

$|u-v|=\sqrt{\left ( 2-1\right )^2+\left ( 1-k\right )^2}=1$

squaring both side

$1^{2}+\left ( 1-k\right )^2=1$

$k^2-2k+1=0$

$\left ( k-1\right )^2=0$

k=1

$\left ( ii\right )$

angle between u and v is 90 i.e. orthogonal

$u\dot v=0$

$\left ( 1\hat{i}+k\hat{j}\right )\dot \left ( 2\hat{i}+1\hat{j}\right )$ =0

2+k=0

k=-2

$\left ( iii\right )$

angle between u & v is $\frac{\pi }{3}$

$u\dot v=|u||v|cos\left (\frac{\pi }{3}\right )$

$|u|=\sqrt{1^2+k^2}$

$|v|=\sqrt{2^2+1^2}$

$2+k=\left ( \sqrt{1+k^2}\right )\left ( \sqrt{5}\right )cos\left ( \frac{\pi }{3}\right )$

$\left ( 4+2\right )^2=\left ( 1+k^2\right )5$

$k^2-16k-11$ =0

k= $8\pm 5\sqrt{3}$

7 0

3 years ago