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2 years ago

Helppp will give brainless 35points

Mathematics

2 answers:

Ugo [173]2 years ago

6 0

Answer:

$\boxed{question \: number \: \to 6} \\ \boxed{ w = 72} \\ \boxed{ x =144 } \\ \boxed{ y = 108}$

Step-by-step explanation:

$y + w + y + w = 360 \to \sum \: of \: angles \\ y = \: \boxed{opp \: y} \to \: vertically \: opposite \: angles \: are \: equal \\ w = \: \boxed{opp \: w} \to \: the \: same \: reason \: as \: y\\ hence \to \\ 2(w+ y) = 360 \\ w + y = 180 \\ but \: 5w = 360 \to \: angles \: at \: a \: point \\ w = \frac{360}{5} \\ \boxed{w = 72} \\ therefore \to \\ w + y = 180 \\ 72 + y = 180 \\ y = 180 - 72 \\ \boxed{ y = 108} \\ hence \: \boxed{x} \: is \: given \: by \to \\y + x + y = 360 \to \: angles \: at \: a \: point \\108 + x + 108 = 360 \\ x = 360 - 216 \\ \boxed{ x = 144}$

♨Rage♨............You can also ask me the other questions separatly ........cos i cant cover all in this one.♨

Taya2010 [7]2 years ago

6 0

Answer:

why 18 not 35

Step-by-step explanation:

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1 year ago

What is the answer for -12+x/11=-3

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2 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

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