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irina1246 [14]
3 years ago
11

Make v the subject of the formula in H=m(v²-u²)/2gx​

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0

Answer:

v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Step-by-step explanation:

The given formula is :

H=\dfrac{m(v^2-u^2)}{2gx}

We need to find the formula for v.

Cross multiplying the given formula.

H\times 2gx=m(v^2-u^2)

Dividing both sides by m. So,

\dfrac{H\times 2gx}{m}=\dfrac{m(v^2-u^2)}{m}\\\\(v^2-u^2)=\dfrac{H\times 2gx}{m}

Adding both sides by u².

(v^2-u^2)+u^2=\dfrac{H\times 2gx}{m}+u^2\\\\v^2=\dfrac{H\times 2gx}{m}+u^2\\\\\text{So},\\\\v=\sqrt{\dfrac{H\times 2gx}{m}+u^2}

Hence, this is the required formula.

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polet [3.4K]

Answer:

9(p + q)(9p + 9q - 1)

Step-by-step explanation:

Given

81(p + q)² - 9p - 9q ← factor out - 9 from these 2 terms

= 81(p + q)² - 9(p + q) ← factor out 9(p + q) from each term

= 9(p + q)(9(p + q) - 1)

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8 0
3 years ago
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Nadusha1986 [10]

Answer:

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Step-by-step explanation:

2x+x+5-35=180

3x-30=180

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3 0
3 years ago
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8 0
3 years ago
Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
8090 [49]

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

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I hope this helps.
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