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Tcecarenko [31]
3 years ago
14

Cot? 2x + cos2x + sin’ 2x = csc? 2x Need help with 40

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

\rule{100mm}{0.1mm}

    \cot^2(2x)+\cos^2(2x)+\sin^2(2x)=\csc^2(2x)

\dfrac{\cos^2(2x)}{\sin^2(2x)} +[(\cos^2(2x)+\sin^2(2x)]=\csc^2(2x)

                               \dfrac{\cos^2(2x)}{\sin^2(2x)} +1=\csc^2(2x)

                    \dfrac{\cos^2(2x)+\sin^2(2x)}{\sin^2(2x)}=\csc^2(2x)

                                    \dfrac{1}{sin^2(2x)} =\csc^2(2x)

                                     \boxed{\csc^2(2x)=\csc^2(2x)} ✔

\rule{100mm}{0.1mm}

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The number of pieces The customer will need actually is 38 tiles

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Step-by-step explanation:

To solve the problem we will do these steps

1. Change the dimensions of the room from feet to inches

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∴ The dimensions of the sun room are 96" by 114"

The area of a rectangle is length × width

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∵ The dimensions of a tile are 12" by 24"

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∵ The number of tiles = Area room ÷ area tile

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<em>The number of pieces The customer will need is 38 tiles</em>

<u><em>V.I.N:</em></u>

The tiles come in boxes each box contains 9 pieces

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∴ He will need to buy 5 boxes with 45 tiles

<em>The number of tiles in boxes is 45 tiles</em>

Learn more:

You can learn more about the area of some figures in brainly.com/question/4459688

brainly.com/question/4354581

#LearnwithBrainly

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