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3 years ago

Help please :( I tried working on this for a while and haven’t got near anything close to the answer D:

Mathematics

1 answer:

valina [46]3 years ago

4 0

Answer:

a) 11x

b) x=14

Step-by-step explanation:

So we know that there are 2 shapes

a triangle and a rectangle

The area for a triangle is b*h/2

The area for a rectangle is L*W

Now we know the height and the base for the triangle and we know the length and width of the rectangle

So lets do the triangle first

So we know the height is 6 and the base is x.

Now 6*x is 6x.

And 6x/2 is 3x.

now we know that the triangle angle is equal to 3x

now the rectangle is 8*x

which is 8x

now we know the rectangle (8x)

now we add them up since it’s asking for the total area

Now its 11x

So thats part A, 11x is the expression

A expression is Without a equal sign and it’s used as a basic formula for he unknown variable

The equation now for part b is

11x=154

now that is the equation becuase we sole for x and we an use the previous expression becuase now we know what the area is.

now solve for x and you’ll get x=14.

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4, 10, 16, 22, 28,...<br> C32,38<br> O32, 40<br> C34, 38<br> C34, 40

Nataly_w [17]

Answer:

the answer is 34, 40

Step-by-step explanation:

10-4=6

16-10=6

22-16=6

28-22=6

28+6=34

34+6=40

8 0

4 years ago

x ≡ 185 (mod 2) x ≡ 185 (mod 3) x ≡ 26 (mod 3) x ≡ 26 (mod 5) x ≡ −9 (mod 2) x ≡ −9 (mod 5) −→ x ≡ 1 (mod 2) x ≡ 2 (mod 3) x ≡ 2

Free_Kalibri [48]

Answer:

The latex conversion is given below.

Step-by-step explanation:

Given,

$x \equiv 26$ (mod 2)

$x \equiv 185$ (mod 3)

$x \equiv 26$ (mod 3)

$x \equiv 26$ (mod 5)

$x \equiv -9$ (mod 2)

$x \equiv -9$ (mod 5)

$\rightarrow x \equiv 1$ (mod 2)

$x \equiv 2$ (mod 3)

$x \equiv 1$ (mod 5)

$\rightarrow x \equiv 1$ (mod 2)

To write in latex the language wll be,

$x \equiv 26$$($mod $2)$

$x \equiv 185 $$($mod 43)$

$ x \equiv 26$$($mod $3)$

$x \equiv 26$$($mod $5)$

$x \equiv -9$$($mod $2)$

$x \equiv -9$$($mod $5)$

$\rightarrow x \equiv 1$$($mod $2)$

$x \equiv 2$$($mod $3)$

$x \equiv 1$$($mod $5)$

$\rightarrow x \equiv 1$$($mod $2)$

Since all mathematical terms coverred by $$.

6 0

3 years ago

An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 100100 engin

Margaret [11]

Answer:

Null hypothesis: $\mu \geq 7.3$

Alternative hypothesis: $\mu < 7.3$

$z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=7.2$ represent the sample mean

$\sigma=0.81$ represent the population standard deviation

$n=100$ sample size

$\mu_o =7.3$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean pressure is lower than the specificated value 7.3, the system of hypothesis are :

Null hypothesis: $\mu \geq 7.3$

Alternative hypothesis: $\mu < 7.3$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235$

4) P-value

Since is a one-side lower test the p value would given by:

$p_v =P(z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.

7 0

3 years ago

What is the volume of this sphere

ruslelena [56]

Answer:

3052.08 m³

Step-by-step explanation:

$\boxed{volume \: of \: sphere = \frac{4}{3}\pi {r}^{3} }$