All categories

3 years ago

Help please :( I tried working on this for a while and haven’t got near anything close to the answer D:

Mathematics

1 answer:

valina [46]3 years ago

4 0

Answer:

a) 11x

b) x=14

Step-by-step explanation:

So we know that there are 2 shapes

a triangle and a rectangle

The area for a triangle is b*h/2

The area for a rectangle is L*W

Now we know the height and the base for the triangle and we know the length and width of the rectangle

So lets do the triangle first

So we know the height is 6 and the base is x.

Now 6*x is 6x.

And 6x/2 is 3x.

now we know that the triangle angle is equal to 3x

now the rectangle is 8*x

which is 8x

now we know the rectangle (8x)

now we add them up since it’s asking for the total area

Now its 11x

So thats part A, 11x is the expression

A expression is Without a equal sign and it’s used as a basic formula for he unknown variable

The equation now for part b is

11x=154

now that is the equation becuase we sole for x and we an use the previous expression becuase now we know what the area is.

now solve for x and you’ll get x=14.

You might be interested in

What is 574 ÷ 82 my math say use compatible numbers to round first then awnser the actual queston

Svetradugi [14.3K]

Answer: 7 explanation:574 $%$ %82=7 7x82=574

7 0

3 years ago

Read 2 more answers

On Friday, the temperature was 82°F. The temperature changed by –2°F on Saturday, and then it changed by 5°F on Sunday. What was

postnew [5]

Answer:

the temp on Sunday was 85, it changed by going down 2 degrees, and up 5 degrees

Step-by-step explanation:

when it says -2 degrees F its basically saying subtract 2, and then go on and add 5

4 0

3 years ago

Read 2 more answers

For each of the following studies, say whether you would use a t test for dependent means or a t test for independent means.

Shtirlitz [24]

Answer:

1. T test for independent means

2. T test for dependent means

3. T test for dependent means

Step-by-step explanation:

In number 1, the two groups are unrelated. The first group has 25 subjects and they're all unemployed. The second group has 24 subjects and their employment status is not stated and might not be the same all through. Also, the first group is receiving a new type of job skills program while the second group is taking the standard job skills program.

- The groups in the experiment are unrelated

- The tests in the research are unrelated

- The purpose of the research is unreasonable - the researcher seeks to measure how well all 49 subjects perform on 'a' job skills test! No comparison between the scores or mean scores of the two groups.

In number 2, the researcher uses the same subjects and also measures the same variable but twice. This is a good example of a study where the t test for dependent means can be taken. Same applies in case 3.

5 0

3 years ago

Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.

gladu [14]

Answer:

Vertical asymptote: $x=3$

Horizontal asymptote: $f(x) =2$

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

$f (x) = -\dfrac{1 }{ x-3} +2$

One root, $x = 3.5$

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

$0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5$

One root, $x = 3.5$

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is $\frac{1}{x-3}$ .

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) $\rightarrow \infty$ .

$-\dfrac{1 }{ x-3} +2 \rightarrow \infty$

It is possible only when

$x-3=0\\\Rightarrow x=3$

$\therefore$ vertical asymptote: $x=3$

Horizontal Asymptote is the value of f(x) , where value of x $\rightarrow \infty$ .

$x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2$

$\therefore$ Horizontal asymptote: $f(x) =2$

Please refer to the graph of given function as shown in the attached image.

5 0

3 years ago

I need help with all of them and if you can't help with all of them just answer one of them please. Look at the picture

likoan [24]

All you have to do is substitute the y value from the 1st equation into the second equation and solve...

a) y= 2-x
5x + 4y = 5

Substitute (2-x) into the second equation anywhere there is a y...

5x + 4y = 5
5x + 4(2-x) = 5

Now solve

5x + 8 - 4x = 5
5x - 4x + 8 = 5
x + 8 = 5
x = -3

Now that you have a solution for x, substitute -3 into either of the original equations anywhere there is an x then solve for y...

y = 2 - x
y = 2 - (-3)
y = 2+3 = 5

You solved for x and got -3 and solved for y and got 5, so your solution set is
(-3, 5).

Now check it by substituting both numbers into one of the original equations and you should have a true statement if it is correct...

y = 2 - x
5 = 2 - (-3)
5 = 2+3
5 = 5

True statement... it checks!

note* during the check, if the equation would have worked out to something like 2 = 5, then that is a false statement therefore the solution set would be wrong and you'd have to go back and find the mistake.

5 0

3 years ago