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3 years ago

A rock is an example of a solid because

Physics

1 answer:

8_murik_8 [283]3 years ago

8 0

Answer:

The key is that solids hold their shape and they don't flow like a liquid. A rock will always look like a rock unless something happens to it.

Solids can hold their shape because their molecules are tightly packed together.

Explanation:

Yes; it is a solid

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PLEASE HELP. GRAVITY QUESTION, WRITTEN RESPONSE.

Rina8888 [55]

1) Forces acting on your body: force of gravity and normal reaction

2) Due to Newton's second law, N = mg

Explanation:

When you sit on the computer, there are only two forces acting on you:

The force of gravity, acting downward, of magnitude $W=mg$ , where m is your mass and $g=9.8 m/s^2$ is the acceleration due to gravity, downward
The normal reaction exerted by the chair on you, $N$ , acting upward

Your body is in equilibrium (it doesn't move), this means that the two forces balance each other, therefore:

$N-mg=0\\N=mg$

We can now apply Newton's second law of motion to this situation; this law states that the net force acting on a body is equal to the product between its mass and its acceleration. Mathematically,

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

In this situation, the net force is

$\sum F = N-mg$

So the equation becomes

$N-mg=ma$

However, we observe that your body is at rest; therefore, the acceleration is zero:

a = 0

And therefore,

$N-mg=0\\N=mg$

Learn more about forces:

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#LearnwithBrainly

4 0

4 years ago

An atomic nucleus is composed of

musickatia [10]

Answer:

84 protons and 128 neutron

8 0

3 years ago

A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one

alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R= $13\Omega$

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper wire=Sum of resistance of two piece of wires

$r+7r=13$

$8r=13$

$r=\frac{13}{8}$ ohm

Resistance of long piece of wire= $7\times\frac{13}{8}=\frac{91}{8}\Omega$

Resistance of short piece of wire = $\frac{13}{8}\Omega$

Resistivity of wire and cross section area of wire remains same .

Let L be the total length of wire and L' be the length of short piece of wire.

We know that

$R=\frac{\rho L}{A}$ = $\frac{\rho}{A}L=KL$

$\frac{R}{L}=K$

Where K= $\frac{\rho}{A}$ =Constant

Using the formula

$\frac{13}{L}=\frac{\frac{13}{8}}{L'}$

$\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}$

$L'=\frac{L}{8}$

Length of short piece of wire=L'= $\frac{L}{8}$

Length of long piece of wire= $L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L$

% of length of short piece of wire= $\frac{\frac{L}{8}}{L}\times 100=12.5%$ %

The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

8 0

4 years ago

A wire of resistivity rhorho must be replaced in a circuit by a wire of the same material but 4 times as long. If, however, the

kap26 [50]

The resistivity of a wire is given by:

$R=\rho\frac{l}{\pi r^2}$

Where $\rho$ is the electrical resistivity of the wire, $l$ is the length of the wire and r is the radius os the wire, Recall that $r=\frac{d}{2}$ . So:

$R=\rho\frac{l}{\pi(\frac{d}{2})^2}\\R=4\rho\frac{l}{\pi d^2}$

We have $l'=4l, \rho'=\rho, R'=R$ . Thus:

$R'=4\rho'\frac{l'}{\pi d'^2}\\R=4\rho\frac{4l}{\pi d'^2}\\4\rho\frac{l}{\pi d^2}=4\rho\frac{4l}{\pi d'^2}\\\frac{1}{d^2}=\frac{4}{d'^2}\\d'^2=4d^2\\d'=2d$

The diameter of the new wire must be twice of the original wire.

5 0

3 years ago

What is the independent variable? What is the dependent variable? Please help!

e-lub [12.9K]

graphic too wide.

indep variable is one you control

dep var is what happens

7 0

3 years ago