Answer:
The mass of the rod is 16 kg.
Explanation:
Given that,
The length of a rod, L = 3 m
The moment of inertia of the rod, I = 12 kg-m²
We need to find the mass of the rod. The moment of inertia of the rod of length L is given by :
Where
M is mass of the rod
So, the mass of the rod is 16 kg.
Answer:
#See solution for details.
Explanation:
Newton's Second law of motion states that :- the rate of change of momentum is directly proportional to the force applied on an object or system..
The force applied on an object of mass m is directly proportional to the product of mass and acceleration:
-Let be the initial momentum and be the final momentum.
#also let be the initial velocity and the final.
Momentum,:
#where k is the constant of proportionality. Given the direct proportion, k=1.
#The unit is in kgm/s but usually equated to N, 1kgm/s=1N
It's a combination of all those things. probably because we are taught from an early age to write in an academic fashion, giving balanced arguments and a conclusion. When speaking from the heart, there is no opposing argument nor is there a conclusion, just emotion.
In other words a infinitesimal segment dV caries the charge
<span>dQ = ρ dV </span>
<span>Let dV be a spherical shell between between r and (r + dr): </span>
<span>dV = (4π/3)·( (r + dr)² - r³ ) </span>
<span>= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) </span>
<span>= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) </span>
<span>drop higher order terms </span>
<span>= 4·π·r²·dr </span>
<span>To get total charge integrate over the whole volume of your object, i.e. </span>
<span>from ri to ra: </span>
<span>Q = ∫ dQ = ∫ ρ dV </span>
<span>= ∫ri→ra { (b/r)·4·π·r² } dr </span>
<span>= ∫ri→ra { 4·π·b·r } dr </span>
<span>= 2·π·b·( ra² - ri² ) </span>
<span>With given parameters: </span>
<span>Q = 2·π · 3µC/m²·( (6cm)² - (4cm)² ) </span>
<span>= 2·π · 3×10⁻⁶C/m²·( (6×10⁻²m)² - (4×10⁻²m)² ) </span>
<span>= 3.77×10⁻⁸C </span>
<span>= 37.7nC</span>
Answer:
Height of ramp = 17.49 m
Explanation:
We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering horizontal motion of skier
Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.
The vertical distance traveled in 1.909 seconds is the height of ramp
Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8 , time = 1.909 s and we need to find displacement.
So height of ramp = 17.49 m