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3 years ago

What increases the ability to see at night?

Physics

2 answers:

Amanda [17]3 years ago

4 0

B is correct :)

Hope this helps!

antiseptic1488 [7]3 years ago

3 0

B is you answer sorry i dont quite know how to explain it in a way that you and anybody else would understand it.

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6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hour

Kisachek [45]

Answer:

Total distance, $d=\dfrac{xyt}{(x+y)}$

Explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to, $\dfrac{d}{x}$

Similarly, when he move back to home, time taken is equal to $\dfrac{d}{y}$

Total time taken is equal to :

$\dfrac{d}{x}+\dfrac{d}{y}=t$

$d(\dfrac{1}{x}+\dfrac{1}{y})=t$

$d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}$

$d=\dfrac{xyt}{(x+y)}$

So, the distance he speed in walking and jogging is $\dfrac{xyt}{(x+y)}$ . Hence, this is the required solution.

8 0

3 years ago

A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a l

zalisa [80]

Answer:

Explanation:

Expression for time period of pendulum is given as follows

$T=2\pi\sqrt{\frac{l}{g} }$

where l is length of pendulum and g is acceleration due to gravity .

Putting the given values for first place

$2.67=2\pi\sqrt{\frac{l}{9.77} }$

Putting the values for second place

$T=2\pi\sqrt{\frac{l}{9.81} }$

Dividing these two equation

$\frac{T}{2.67} =\sqrt{\frac{9.77}{9.81} }$

T = 2.66455 s.

5 0

3 years ago

The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that

Furkat [3]

Answer:

Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth

5 0

3 years ago

An advertisement claims that a certain 1200kg can accelerate from rest to a speed of 25 m/s in a time of 8s. What average power

expeople1 [14]

Answer: 3MW

Explanation:

W = 1/2 mv^2

W = 0.5 x 1200 x 25^2 = 375 kW

T = 8s

P= 335 x 10^3 x 8 = 3,000 kW = 3MW

3 0

3 years ago

Planet-X has a mass of 3.42×1024 kg and a radius of 8450 km. What is the First Cosmic Speed i.e. the speed of a satellite on a l

tino4ka555 [31]

Answer:

First cosmic speed = 5195.74m/s

Second cosmic speed = 7346.05m/s

The raduis of the synchronous 0rbit of satellite is 2.80×10^7m

Explanation:

The first cosmic speed Is determined using the Orbital speed equation which is given by:

V = Sqrt(GM/r)

Where G = gravitational constant = 6.67 ×10^-11

M = Mass of planet

r = radius of the planet

V = Sqrt (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt (2.28×10^14)/(8450×10^3)

V = Sqrt ( 26995739.64)

V = 5195.75m/s

The second cosmic speed is given by :

V = Sqrt(2 × GM)/r

V = Sqrt (2 × (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt( 4.5×10^14)/ (8450×10^3)

V = Sqrt(53964497.04)

V = 7346.05m/s

The raduis of the synchronous orbit if the satellite around the planet is given by:

r = Cuberoot(T^2GM/4 pi r^2where T is the period of rotation of the planet in second

Given :

T = 17.1 hours converting to seconds

T = 17.1 ×60 ×60 = 61560 seconds

Substituting into the equation

r = Cuberoot ([(61560)^2×(6.67×10^-11)(3.42×10^24)/ (4 ×3.142×r^2)]

r = 2.80×10^7m

5 0

3 years ago

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