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suter [353]
3 years ago
7

What is the independent variable? What is the dependent variable? Please help!

Physics
1 answer:
e-lub [12.9K]3 years ago
7 0

graphic too wide.

indep variable is one you control

dep var is what happens

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If the acceleration of an object is zero at some instant in time, what can be said about its velocity at that time? 1. It is neg
Mkey [24]

3. It is not changing at that time

Explanation:

If the acceleration of a body is zero at some instant in time, it implies that the velocity is not changing at that point in time. Velocity is the rate of change of displacement with time.

✓Acceleration and velocity shares a very close relationship.

✓ For a body to accelerate, the velocity must change. Acceleration is defined as the rate of change of velocity with time.

✓If at any point, a body moves with constant velocity i.e the velocity does not change with time, the acceleration becomes zero.

✓ For acceleration to occur, a body must change velocity.

Learn more:

Acceleration brainly.com/question/6323625

#learnwithBrainly

5 0
3 years ago
Two point charges are placed on the x axis as follows: charge q1=+3.75nc is located at x=0.205m and charge q2=−5.60 nc is at x=+
Mademuasel [1]
I might have did mistake with calculations but this is how you should do.

6 0
3 years ago
What is the velocity of a 50kg skater if her momentum is 225kg. m/s?
Gnom [1K]

|Momentum| = (mass) x (speed)

225 kg-m/s =(50kg) x (speed)

Divide each side by (50kg):  Speed=(225 kg-m/s) / (50 kg) = 4.5 m/s .

Regarding the velocity, nothing can be said other than the speed, because
we have no information regarding the direction of the object's motion.

8 0
3 years ago
Read 2 more answers
A care package is dropped from an airplane flying at 1000 m above sea level with a velocity of 200 m/s to an island. If it takes
ikadub [295]

Answer:3000

Explanation:

4 0
3 years ago
A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite
sladkih [1.3K]

Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

       The gravitational force is  F_g  = 6600 \ N

The kinetic energy of the satellite is mathematically represented as

       KE  =  \frac{1}{2} * mv^2

where v is the speed of the satellite which is mathematically represented as

     v  = \sqrt{\frac{G  M}{r^2} }

=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

=>    KE  =  \frac{ 1}{2} *F_g * r

substituting values

       KE  =  \frac{ 1}{2} *6600 * 2.3*10^{7}

         KE  =  7.59  *10^{10} \  J

 

7 0
3 years ago
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