Answer: The required number of large order of chicken tenders is 5.
Step-by-step explanation: Given that Sheila loves to eat chicken tenders. A small order comes with 5 chicken tenders, and a large order comes with 8 chicken tenders.
Last month, Sheila ordered chicken tenders a total of 7 times. She received a total of 50 chicken tenders.
We are to find the number of large chicken tenders received by Sheila.
Let x and y represents the number of small orders and large orders respectively of chicken tenders.
Then, according to the given information, we have

and
![5x+8y=50\\\\\Rightarrow 5(7-y)+8y=50~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\Rightarrow 35-5y+8y=50\\\\\Rightarrow 3y=50-35\\\\\Rightarrow 3y=15\\\\\Rightarrow y=\dfrac{15}{3}\\\\\Rightarrow y=5.](https://tex.z-dn.net/?f=5x%2B8y%3D50%5C%5C%5C%5C%5CRightarrow%205%287-y%29%2B8y%3D50~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7BUsing%20equation%20%28i%29%7D%5D%5C%5C%5C%5C%5CRightarrow%2035-5y%2B8y%3D50%5C%5C%5C%5C%5CRightarrow%203y%3D50-35%5C%5C%5C%5C%5CRightarrow%203y%3D15%5C%5C%5C%5C%5CRightarrow%20y%3D%5Cdfrac%7B15%7D%7B3%7D%5C%5C%5C%5C%5CRightarrow%20y%3D5.)
Thus, the required number of large order of chicken tenders is 5.
Answer:
b
Step-by-step explanation:
given s(t) = t³ - 5t then
v(t) = s'(t) = 3t² - 5 and
v(3) = 3(3)² - 5 = 22 m / s, and
a(t) = v'(t) = 6t, then
a(3) = 6 × 3 = 18 m / s²
1.
Answer C. (8)
2.
Answer C. [6x^(4/3)]
3.
Answer D. (the one with 36x²)
4.
Answer B. (2a^(2/3)b²)
5.
Answers C. and D.
the awnser to your question is 48 because you are just subtracting