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olchik [2.2K]
2 years ago
9

Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags. Because of variability in the manufactu

ring process, the bags often contain slightly more, or less, than 32 ounces of green beans. An inspector takes a random sample of 25 bags of green beans of each type and records their weights. The weights and their relative frequencies are summarized in the histograms. 2 histograms comparing brand A and brand B of green beans. The median weight for brand B is less than the median weight of brand A. Which of the following is a true statement when comparing the bags of green beans? The median weight for both types is between 32.1 and 32.2 ounces. The median weight for both types is between 32.0 and 32.1 ounces. The median weight for brand B is less than the median weight of brand A. The median weight for brand B is greater than the median weight of brand A.
Mathematics
1 answer:
Talja [164]2 years ago
6 0

Answer:

C The median weight for brand B is less than the median weight of brand A.

Step-by-step explanation:

Just did it on edgenunity

You might be interested in
The data set below has 6 values.
r-ruslan [8.4K]

Answer:

I belive the answer is 5

Step-by-step explanation:

4 0
3 years ago
The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

5 0
3 years ago
If 0° ≤ θ ≤ 90° and cosθ = 11/15 , what is the value of sin (90° - θ)?
igor_vitrenko [27]
11/15=0.7333
cos^{-1}(0.7333) =42.83342
sin(90-47.166572) = 0.7333

first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!

since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!
7 0
3 years ago
Read 2 more answers
Please help it is due tomorrow.
svlad2 [7]
R = radius of basketball
r = radius of tennis ball 
R = 3.6r cube both sides
the ratio of the radii is 1: 3.6
cube both sides to find the ratio of the volumes 
1 : 46.656 ( this many times greater)
6 0
2 years ago
I’m pretty sure the answer is a ?
irina [24]
I believe that it’s B
7 0
2 years ago
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