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torisob [31]
2 years ago
15

Work out the temperature

Mathematics
1 answer:
VashaNatasha [74]2 years ago
4 0

Answer:

a) -4

b) 4

c)0

Step-by-step explanation:

a) It had fallen by 9 ,therefore it would be 5 -9 = -4

b)mode is the most repetitive number that is 4

c) the median is the middle value.First arrange the numbers orderly then get the odd number that is 0.

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3xy<br> А.<br> у<br> 2х<br> ху.<br> Simplify expression
Anika [276]
Nah fam math hard math can solve its own problems 82773919
3 0
2 years ago
Which equation calculates the number of 1/3-foot pieces that can be cut from a piece of
harina [27]

Answer:

7:\dfrac{1}{3}=21 pieces

Step-by-step explanation:

Suppose you have a 7 feet long wood.

You need to find how many \frac{1}{3}-foot pieces can be cut from this wood.

To find this number of pieces, you have to divide the whole length of the wood by the length of one piece:

7:\dfrac{1}{3}=\dfrac{7}{1}\cdot \dfrac{3}{1}=21

8 0
3 years ago
Gina puts $ 4500 into an account earning 7.5% interest compounded continuously. How long will it take for the amount in the acco
Elza [17]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5150\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years \end{cases}

5150=4500e^{0.075\cdot t} \implies \cfrac{5150}{4500}=e^{0.075t}\implies \cfrac{103}{90}=e^{0.075t} \\\\\\ \log_e\left( \cfrac{103}{90} \right)=\log_e(e^{0.075t})\implies \log_e\left( \cfrac{103}{90} \right)=0.075t \\\\\\ \ln\left( \cfrac{103}{90} \right)=0.075t\implies \cfrac{\ln\left( \frac{103}{90} \right)}{0.075}=t\implies\stackrel{\textit{about 1 year and 291 days}}{ 1.8\approx t}

4 0
1 year ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
2 years ago
An amount of 41,000 is borrowed for 15 years at 8.5% interest, compounded annually. If the loan is paid in full at the end of th
bazaltina [42]

Answer: $139390 must be paid back.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = amount to be played back at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount borrowed.

From the information given,

P = 41000

r = 8.5% = 8.5/100 = 0.085

n = 1 because it was compounded once in a year.

t = 15 years

Therefore,

A = 41000(1 + 0.085/1)^1 × 15

A = 41000(1 + 0.085)^15

A = 41000(1.085)^15

A = $139390

3 0
2 years ago
Read 2 more answers
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