Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
3+37=40
3/40×1200=90kg
37÷40×1200=1110kg
Step-by-step explanation:
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Answer:
B=45
Step-by-step explanation:
let the supplamentary angle of <A is <d
180-A=d
180-135=d
45=d
90+d+B=180
90+45+B=180
135+B=180
B=180-135
B=45
Givens
Area = 200 square feet
Formula
A = s^2
Soluton
s^2 = 200 square feet.
Take the square root of both sides.
square root s^2 = square root (200)
You should use a calculator to find the square root of 200
√
200
=
is the way to put it into the calculator.
s = 14.1 feet on each side. <<<<< Answer
Answer
it could be 73/x
Step-by-step explanation:
