The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
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Answer:
<em>The fact that the left ventricle of the heart is thicker than the right ventricle reveals that it pumps blood against a greater resistance. -C.</em>
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Evaporation of ocean water and formation of sea ice both increase the salinity of the ocean water.
Answer:(a)elastase
Explanation:
Elastase is a protease enzyme the function involves the cleavage of peptide bonds after amino acids with small side chains. This is responsible for cleaving the peptide bonds between the elastin fibers and aids in digestion of the elastic protein.
Thus the elastase cleaves the protein fibers this can be said that the elastase is a non-fibrous protein.
Some features might be feathers, thin bones, they are lighter to make flying easier.
