Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
Answer:
541.7 (m2)
Step-by-step explanation:
Applying the sine theorem:
WV/sin(X) = XV/sin(W)
=> WV = XV*sin(X)/sin(W) = 37*sin(50)/sin(63) = 31.81
Angle V = 180 - X - W = 180 - 50 - 63 = 67
Denote WH is a height of the triangle VWX, H lies on XV
=> WH = WV*sin(V) = 31.81*sin(67) = 29.28
=> Area of triangle VWX is calculated by:
S = side*height/2 = XV*WH/2 = 37*29.28/2 = 541.7 (m2)
Answer:
Step-by-step explanation:
According to congruent chords and arcs theorem, if 
then 
.
This means that 
Thus:
(full circle = 360°)
Plug in the values into the equation
Add like terms
Subtract 36 on both sides
Divide both sides by 12
The answer is 1 Bcuz u have to first plug in -4 for f then solve the equation by adding like terms and dividing
<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
