Answer:
1. y = 11
x = -48
2. a =8
b= -10
3. x= 1
y= 2
Step-by-step explanation:
1 . 6x + 5y = 7
x-y= 3
6x+5y = 7
6x-6y =18
-1y = - 11
6x + 5y = 7
y = 11
6x + 55 = 7
6x = -48
x = -48
Answer:
sorry never seen this
Step-by-step explanation:
Answer:
V= 105cm^3
Step-by-step explanation:
V=volume
(1/3)V+40=(5/7)V
(5/7)V-(1/3)V=40
(15/21)V-(7/21)V=40
(8/21)V=40
(21/8)(8/21)V=(21/8)(40
V=21*5
V=105 cm3
(1/3)(105)=35, 35+40=75, 75/105=15/21=5/7
Answer:
3:2
Step-by-step explanation:
3 females every 2 males
<h3>
Answer: 53%</h3>
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Explanation:
The question asks "What percent of females participate in extracurricular activities?" This means we only focus on the second column. There are 36 women, and of this total, 19 are in extracurricular activities.
Dividing the two values leads to approximately 19/36 = 0.52777 which rounds to 0.53
Then we move the decimal to the right two spots to get 53%
Roughly 53% of the female students participate in extracurricular activities.
