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Irina18 [472]
3 years ago
5

PLEASE HELP ME!!!!! This is important

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Answer: the answer is 80 cubic inches.

Step-by-step explanation:

To find the volume of a cube, you have to multiply length, width, and height. Therefore that is 4x5x4= 80 cubic inches

mariarad [96]3 years ago
7 0
Answer is: 80 cubic in.

Formula- L x W x H
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Which of the following is a solution to<br> the equation 0 = x2 – 8x – 13?
Fed [463]

Answer:

x= 32 ± √29

Step-by-step explanation:

x² - 8x - 13 = 0

ax² + bx + c = 0

Comparing equations we get,

a=1

b=(-8)

c=(-13)

Using quadratic formula,

________

x= b² ± √ b²-4ac

—————————

2a

Substituting the values

__________

x= 64 ± √( 64 + 52)

______________

2

= 32 ± √29

Hope this answer helps you....

5 0
4 years ago
What is 2.3 (3 reapeating )as a fraction
Eddi Din [679]

The answer is 2\frac{1}{3}.

.\frac{}{3} equals \frac{1}{3}, so by adding 2 the answer is 2\frac{1}{3}.

7 0
3 years ago
Read 2 more answers
The values (9.4,11) and (11,y) are from an inverse variation. Find the missing value and round to the nearest hundredth.
marusya05 [52]

Answer: 9.4

Step-by-step explanation:

Here the x-coordinates and y-coordinates have the inverse relation.

⇒ x\propto\frac{1}{y}

⇒ x=\frac{k}{y}

Where k is variation constant.

Since, point (9.4, 11) is from the inverse variation,

Therefore, this point must be satisfy the above condition,

That is,    9.4=\frac{k}{11}

k=103.4

Thus, the relation between the coordinates is,

x=\frac{103.4}{y}

Put x = 11, in the above function,

11=\frac{103.4}{y}

y=\frac{103.4}{11}=9.4

3 0
3 years ago
Read 2 more answers
Write an equation for the line in point-slope and slope-intercept forms.
kobusy [5.1K]

point-slope form: y-y₁ = m(x-x₁)

=============

\rightarrow \sf y - 5 = \dfrac{5}{3} (x-3)

slope-intercept form: y = mx + b

============

\rightarrow \sf y - 5 =  \dfrac{5}{3}(x)+ \dfrac{5}{3}(-3)

\rightarrow \sf y - 5 =  \dfrac{5}{3}(x)-5

\rightarrow \sf y  =  \dfrac{5}{3}(x)-5+5

\rightarrow \sf y  =  \dfrac{5}{3}(x)

6 0
3 years ago
Read 2 more answers
F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist
tester [92]

Answer:

(f - g)(x) = x^2 + x-21

(f - g)(10) = 89

(f/g)(x) = \frac{x^2 - 10}{11 - x}

Step-by-step explanation:

Given

f(x) = x^2 - 10

g(x) = 11  - x

Solving (1): (f-g)(x)

(f - g)(x) = f(x) - g(x)

Substitute values for f(x) and g(x)

(f - g)(x) = x^2 - 10 - (11 - x)

Open Bracket

(f - g)(x) = x^2 - 10 - 11 + x

(f - g)(x) = x^2 -21 + x

Reorder

(f - g)(x) = x^2 + x-21

Solving (2): (f-g)(10)

In (1)

(f - g)(x) = x^2 + x-21

So:

(f - g)(10) = 10^2 + 10-21

(f - g)(10) = 100 + 10-21

(f - g)(10) = 89

Solving (3): (f/g)(x)

(f/g)(x) = \frac{f(x)}{g(x)}

Substitute values for f(x) and g(x)

(f/g)(x) = \frac{x^2 - 10}{11 - x}

6 0
3 years ago
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