Can someone help me please
1 answer:
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Answer:
1)
2)
3)
Step-by-step explanation:
We want to write the equation of the line that passes through the points (7, -4) and (-1, 3) first in point-slope form and then in slope-intercept form.
1)
First and foremost, we will need to find the slope of the line. So, we can use the slope-formula:
Let (7, -4) be (x₁, y₁) and let (-1, 3) be (x₂, y₂). Substitute them into our slope formula. This yields:
Subtract. So, our slope is:
2)
Now, let's use the point-slope form:
We will substitute -7/8 for our slope m. We will also use the point (7, -4) and this will be our (x₁, y₁). So, substituting these values yield:
Simplify. So, our point-slope equation is:
3)
Finally, we want to convert this into slope-intercept form. So, let's solve for our y.
On the right, distribute:
Subtract 4 from both sides. Note that we can write 4 using a common denominator of 8, so 4 is 32/8. This yields:
Subtract. So, our slope-intercept equation is:
And we're done!
Answer:
<h2>y = 6x + 2</h2>Step-by-step explanation:
The slope-intercept form of an equation of a line:
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
<em />
We have the slope <em>m = 6</em>, and the y-intercept <em>b = 2</em>.
Substitute:
