The second one. (B) because i learned about it in 6th grade.
I assume that there is an operato ^ missing in each function and that the right functions are:
f(m) = (m+40)^2 + 10 and
g(m) = (m+12)^2 - 50
C(m) = f(m) + g(m)
To perform that sum you need to expand the two square parentheses, this way:
f(m) = (m+40)^2 + 10 = m^2 + 80m + 1600 + 10 = m^2 + 80m + 1610
g(m) = (m+12)^2 - 50 = m^2 + 24m + 144 - 50 = m^2 +24m + 94
Now you can add f(m) + g(m) = 2m^2 + 104m + 1704
Answer: c(m) = 2m^2 + 104m + 1704
Answer:
thanks
Step-by-step explanation:
appreicate it !
hope you have a great day!