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Hunter-Best [27]
2 years ago
7

HELPPP DUE IN A COUPLE MIN MARKING BRAINLIEST ANSWER ASAP

Mathematics
1 answer:
ankoles [38]2 years ago
4 0

Answer: See explanation

Step-by-step explanation:

15.) -7x + 6 (x - 8/2) - 2(x + 3) + 10

-7x + 6 (x - 4) - 2(x + 3) + 10

-7x + 6x - 24 - 2x - 6 + 10

Bring like terms together

-7x + 6x - 2x - 24 - 6 + 10

-3x - 20

16.) B, C, D

B. 3 (x + 2) + 4x

3x + 6 + 4x = 7x + 6

C. -2 + 4(x + 3)

-2 + 4x + 12 = 4x + 10

D. 3x + 5(x - 1)

3x + 5x - 5

8x - 5

17.) A, B, D

A. 1/5(x - 50)

1/5x - 10

B. 1/6(-x + 12)

-1/6x + 2

D. 1/2(x + 16)

1/2x + 8

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Please help i don't even where to start<br><br>solve for x​
aliina [53]

The radius is 10, so the diameter is 20. This means the parts of the diameter (the chord through the center P) to the left and right of the vertical chord have lengths 16 and 4, respectively.

Because the horizontal chord is a diameter, the vertical chord is cut in half, so its parts above and below the diameter both have length <em>x</em>.

Now, by the intersecting chord theorem,

16×4 = <em>x</em> × <em>x</em>

or

<em>x</em> ² = 64

so that

<em>x</em> = 8

6 0
3 years ago
Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
If m(x) = 4(x - 2), find m(-5)
Nezavi [6.7K]

Answer:

szdg

Step-by-step explanation:

hesre

6 0
3 years ago
Read 2 more answers
How many solutions does this linear system have?
Tanya [424]

Answer:

B (2.5, 0)

Step-by-step explanation:

2x - y = 5 (multiply all by 4)

8x- 4y = 20

-8x - 4y = - 20

eliminate the 4y

8x- 4y = 20

-8x - 4y = - 20

-------------------- –

16x = 40

x = 40/16 = 2.5

now we substitute x with 2.5

2x - y = 5

2(2.5) - y = 5

y = 0

8 0
3 years ago
What is the graph of y=-(x-2)^3-5
natulia [17]
When x=0,
y=-(0-2)^3-5
y=3

When y=0,
(x-2)^3=5
x-2= +/- 5^1/3
x= +/- 5^1/3 +2
x= 3.70997 or x=0.29002

To find the turning point at y, substitute the information that you have found above.

y=-(3.70997-2)^3-5
y=-9.99994

Find the mid-point next as mid-point is also the turning point.

(3.70997+0.29002)÷2=1.999995

Hence, Turning point is (1.999995, 9.99994)

Plot a graph using turning point, y value and the 2-x values.
6 0
3 years ago
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