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gulaghasi [49]
3 years ago
6

How do u solve the area if theres more then one number to multiply

Mathematics
1 answer:
Alex Ar [27]3 years ago
3 0
Do something like his

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\dfrac{1}{n} - \dfrac{1}{n+1} = \dfrac{1}{n(n+1)} \\&#10;&#10; \dfrac{1}{1*2} = \dfrac{1}{1} - \dfrac{1}{2} \\&#10;&#10; \dfrac{1}{2*3} = \dfrac{1}{2} - \dfrac{1}{3} \\&#10;&#10; \dfrac{1}{3*4} = \dfrac{1}{3} - \frac{1}{4} \\&#10;&#10;...\\&#10; \dfrac{1}{n*(n+1)} = \dfrac{1}{n} - \dfrac{1}{n+1} \\&#10;&#10;&#10;&#10;

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\dfrac{1}{1*2} + \dfrac{1}{2*3} +\dfrac{1}{3*4} +...\dfrac{1}{n*(n+1)}=\\&#10; &#10;\dfrac{1}{1}  - \dfrac{1}{n+1} \\&#10;&#10;= \dfrac{n}{n+1} \\&#10;&#10;

if n=100 sum \boxed{= \dfrac{100}{101} }


3 0
3 years ago
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