Answer:
A'=(4,-8)
B'=(4,12)
C'=(-12, -12)
Step-by-step explanation:
Ad 3 to the location you are heading remember first is x then y so (x, y)
X is always left and right
Y is always up or down
<span>Cannot seem to figure out how to Solve , I do know equal sides pair up and you can get an answer from that but do not know what to do from there or where to plug the answer in to get the final answer
However, I have some hints here that you might utilize:
</span><span>diagonals are congruent in isosceles trap
</span><span>
AC = BD
I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
Check on Socratic it might help 12344
Answer:
1. False 2. True
Step-by-step explanation:
For a geometric sequence,
![\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}](https://tex.z-dn.net/?f=%5Cdfrac%7Ba_2%7D%7Ba_1%7D%3D%5Cdfrac%7Ba_3%7D%7Ba_2%7D)
1. The sequence is :
3, 13, 23, 33,...
![\dfrac{13}{3}\ne \dfrac{23}{13}](https://tex.z-dn.net/?f=%5Cdfrac%7B13%7D%7B3%7D%5Cne%20%5Cdfrac%7B23%7D%7B13%7D)
It is not geometric. It is false
2. The sequence is :
5, -25, 125, -625
![\dfrac{-25}{5}=\dfrac{125}{-25}\\\\-5=-5](https://tex.z-dn.net/?f=%5Cdfrac%7B-25%7D%7B5%7D%3D%5Cdfrac%7B125%7D%7B-25%7D%5C%5C%5C%5C-5%3D-5)
So, the sequence is geometric as the common ratio is same. It is true.
Only difference your example has 11 and here it's ten
screenshoot