Answer:
Coding and Hardware Hacking
Explanation:
You can learn coding just as well through a online class or even on the internet through yo*tube than an in person class whereas it would be alot easier learning hardware hacking in person because you are given the opportunity to ask and can be corrected for small mistakes due to the task being manual. Coding can be learnt online independently if needed although so can hardware hacking but having a teacher to correct you and teach you handy tricks from their experience will get you further in that sense.
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
= 
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
Butterfly one I forgot the name metapods evolution
The correct answer is B.UPS
A UPS or Uninterruptable Power supply makes
sure that you have backup in case there is a power outage in your area. It
provides ample time for you to save all files before shut down.
