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3 years ago

8/2(2+2) please help

Mathematics

2 answers:

AnnyKZ [126]3 years ago

6 0

Answer:

The answer is simply is 16.

Step-by-step explanation:

It is important to use PEMDAS. P stands for parenthesis, e stands for exponets, m stands for multiplication, d stands for division, a stands for addition, s stands for subtraction. So, lets start. Do we have any parenthesis? Yes, we do. That is (2+2). Well 2+2 is 4. Now your new equation would be 8/2(4). Do we have any exponets? No. do we have any multiplication? no. Do we have any division? yes.8/2 is 4. so now we have 4(4). And 4 times 4 is 16. Feel free to clarify if you have any questions.

Semenov [28]3 years ago

4 0

Answer:

Step-by-step explanation:

Use the order PEMDAS

So, parenthesises first.

(2 + 2)

= 4

Then divide.

8/2

= 4

Then multiply.

4(4)

= 16

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SHOW YOUR WORK!!

Dmitrij [34]

Answer:

x = -0.846647 or x = -0.177346 or x = 0.841952 or x = 1.58204

Step-by-step explanation:

Solve for x:

5 x^4 - 7 x^3 - 5 x^2 + 5 x + 1 = 0

Eliminate the cubic term by substituting y = x - 7/20:

1 + 5 (y + 7/20) - 5 (y + 7/20)^2 - 7 (y + 7/20)^3 + 5 (y + 7/20)^4 = 0

Expand out terms of the left hand side:

5 y^4 - (347 y^2)/40 - (43 y)/200 + 61197/32000 = 0

Divide both sides by 5:

y^4 - (347 y^2)/200 - (43 y)/1000 + 61197/160000 = 0

Add (sqrt(61197) y^2)/200 + (347 y^2)/200 + (43 y)/1000 to both sides:

y^4 + (sqrt(61197) y^2)/200 + 61197/160000 = (sqrt(61197) y^2)/200 + (347 y^2)/200 + (43 y)/1000

y^4 + (sqrt(61197) y^2)/200 + 61197/160000 = (y^2 + sqrt(61197)/400)^2:

(y^2 + sqrt(61197)/400)^2 = (sqrt(61197) y^2)/200 + (347 y^2)/200 + (43 y)/1000

Add 2 (y^2 + sqrt(61197)/400) λ + λ^2 to both sides:

(y^2 + sqrt(61197)/400)^2 + 2 λ (y^2 + sqrt(61197)/400) + λ^2 = (43 y)/1000 + (sqrt(61197) y^2)/200 + (347 y^2)/200 + 2 λ (y^2 + sqrt(61197)/400) + λ^2

(y^2 + sqrt(61197)/400)^2 + 2 λ (y^2 + sqrt(61197)/400) + λ^2 = (y^2 + sqrt(61197)/400 + λ)^2:

(y^2 + sqrt(61197)/400 + λ)^2 = (43 y)/1000 + (sqrt(61197) y^2)/200 + (347 y^2)/200 + 2 λ (y^2 + sqrt(61197)/400) + λ^2

(43 y)/1000 + (sqrt(61197) y^2)/200 + (347 y^2)/200 + 2 λ (y^2 + sqrt(61197)/400) + λ^2 = (2 λ + 347/200 + sqrt(61197)/200) y^2 + (43 y)/1000 + (sqrt(61197) λ)/200 + λ^2:

(y^2 + sqrt(61197)/400 + λ)^2 = y^2 (2 λ + 347/200 + sqrt(61197)/200) + (43 y)/1000 + (sqrt(61197) λ)/200 + λ^2

Complete the square on the right hand side:

(y^2 + sqrt(61197)/400 + λ)^2 = (y sqrt(2 λ + 347/200 + sqrt(61197)/200) + 43/(2000 sqrt(2 λ + 347/200 + sqrt(61197)/200)))^2 + (4 (2 λ + 347/200 + sqrt(61197)/200) (λ^2 + (sqrt(61197) λ)/200) - 1849/1000000)/(4 (2 λ + 347/200 + sqrt(61197)/200))

To express the right hand side as a square, find a value of λ such that the last term is 0.

This means 4 (2 λ + 347/200 + sqrt(61197)/200) (λ^2 + (sqrt(61197) λ)/200) - 1849/1000000 = (8000000 λ^3 + 60000 sqrt(61197) λ^2 + 6940000 λ^2 + 34700 sqrt(61197) λ + 6119700 λ - 1849)/1000000 = 0.

Thus the root λ = (-3 sqrt(61197) - 347)/1200 + 1/60 (-i sqrt(3) + 1) ((3 i sqrt(622119) - 4673)/2)^(1/3) + (19 (i sqrt(3) + 1))/(3 2^(2/3) (3 i sqrt(622119) - 4673)^(1/3)) allows the right hand side to be expressed as a square.

(This value will be substituted later):

(y^2 + sqrt(61197)/400 + λ)^2 = (y sqrt(2 λ + 347/200 + sqrt(61197)/200) + 43/(2000 sqrt(2 λ + 347/200 + sqrt(61197)/200)))^2

Take the square root of both sides:

y^2 + sqrt(61197)/400 + λ = y sqrt(2 λ + 347/200 + sqrt(61197)/200) + 43/(2000 sqrt(2 λ + 347/200 + sqrt(61197)/200)) or y^2 + sqrt(61197)/400 + λ = -y sqrt(2 λ + 347/200 + sqrt(61197)/200) - 43/(2000 sqrt(2 λ + 347/200 + sqrt(61197)/200))

Solve using the quadratic formula:

y = 1/40 (sqrt(2) sqrt(400 λ + 347 + sqrt(61197)) + sqrt(2) sqrt(347 - sqrt(61197) - 400 λ + 172 sqrt(2) 1/sqrt(400 λ + 347 + sqrt(61197)))) or y = 1/40 (sqrt(2) sqrt(400 λ + 347 + sqrt(61197)) - sqrt(2) sqrt(347 - sqrt(61197) - 400 λ + 172 sqrt(2) 1/sqrt(400 λ + 347 + sqrt(61197)))) or y = 1/40 (sqrt(2) sqrt(347 - sqrt(61197) - 400 λ - 172 sqrt(2) 1/sqrt(400 λ + 347 + sqrt(61197))) - sqrt(2) sqrt(400 λ + 347 + sqrt(61197))) or y = 1/40 (-sqrt(2) sqrt(400 λ + 347 + sqrt(61197)) - sqrt(2) sqrt(347 - sqrt(61197) - 400 λ - 172 sqrt(2) 1/sqrt(400 λ + 347 + sqrt(61197)))) where λ = (-3 sqrt(61197) - 347)/1200 + 1/60 (-i sqrt(3) + 1) ((3 i sqrt(622119) - 4673)/2)^(1/3) + (19 (i sqrt(3) + 1))/(3 2^(2/3) (3 i sqrt(622119) - 4673)^(1/3))

Substitute λ = (-3 sqrt(61197) - 347)/1200 + 1/60 (-i sqrt(3) + 1) ((3 i sqrt(622119) - 4673)/2)^(1/3) + (19 (i sqrt(3) + 1))/(3 2^(2/3) (3 i sqrt(622119) - 4673)^(1/3)) and approximate:

y = -1.19665 or y = -0.527346 or y = 0.491952 or y = 1.23204

Substitute back for y = x - 7/20:

x - 7/20 = -1.19665 or y = -0.527346 or y = 0.491952 or y = 1.23204

Add 7/20 to both sides:

x = -0.846647 or y = -0.527346 or y = 0.491952 or y = 1.23204

Substitute back for y = x - 7/20:

x = -0.846647 or x - 7/20 = -0.527346 or y = 0.491952 or y = 1.23204

Add 7/20 to both sides:

x = -0.846647 or x = -0.177346 or y = 0.491952 or y = 1.23204

Substitute back for y = x - 7/20:

x = -0.846647 or x = -0.177346 or x - 7/20 = 0.491952 or y = 1.23204

Add 7/20 to both sides:

x = -0.846647 or x = -0.177346 or x = 0.841952 or y = 1.23204

Substitute back for y = x - 7/20:

x = -0.846647 or x = -0.177346 or x = 0.841952 or x - 7/20 = 1.23204

Add 7/20 to both sides:

Answer: x = -0.846647 or x = -0.177346 or x = 0.841952 or x = 1.58204

5 0

4 years ago

Solve 3x+5=18 in slope form?

prisoha [69]

There is no such thing as the slope form of an equation with only a single variable.

If 3x + 5 = 18, then x = 4 and 1/3 .

There's only a slope if the equation makes a line on a grapoh.
This equation only makes a single point.

5 0

3 years ago

What is the equation of the line perpendicular to 2x + y = -5 and passes through the point (4, -3)? Write your answer in slope-i

Pie

2x+y= -5 is our equation and it passes through (4, -3)

point-slope formula= y-y1= m(x-x1)

fill in your formula, but flip the slope so its perpendicular. so slope is 1/2.

y+3=1/2(x-4) when i filled the formula in, i used 4 as x1 and -3 as y1.

y+3=1/2x-2 multiply x and -4 by 1/2

y=1/2x-5 subtract 3 from both sides.

Final answer: y=1/2x-5

Also, i'm sorry my answer took so long the bell rang and so I had to leave this alone for a minute. Feel free to ask any questions :)

6 0

3 years ago

Round your answer to the nearest hundredth. с B 40° ? 7 А

igor_vitrenko [27]

Answer:

take 40 degree as reference angle

using sine rule

let opposite be x

sine 40=opposite/hypotenuse

0.64=x/7

0.64*7=x

4.48=x

Step-by-step explanation:

3 0

3 years ago

Which statements are true about a rectangular pyramid with a height of 9 centimeters and a base with the dimensions of 4 centime

Vladimir79 [104]

Answer:

B. The area of the base of the pyramid, B, is 24 centimeters squared.

C. A rectangular prism with the dimensions of 9 centimeters by 4 centimeters by 6 centimeters will have 3 times volume of this pyramid.

Step-by-step explanation:

Given a rectangular pyramid with:

Height=9 cm

Base Dimensions = 4 centimeters by 6 centimeters

Base Area B=4 X 6 =24 Square cm.

Therefore, Option B (The area of the base of the pyramid, B, is 24 centimeters squared) is correct.

Volume of a pyramid = $\frac{1}{3} $ X Base Area X Height$

$=\frac{1}{3} X 24X9=72 cm^3$

Volume of a Prism with the dimensions of 9 centimeters by 4 centimeters by 6 centimeters

=Base Area X Height

=24 X 9

$=216 cm^3$

Now, 216/72=3

Therefore, A rectangular prism with the same dimensions will have 3 times volume of this pyramid

Therefore, Option C is correct.

5 0

3 years ago

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