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inna [77]
3 years ago
12

For the reaction

Chemistry
1 answer:
stepan [7]3 years ago
7 0
Yea lol do that and maybe 71
You might be interested in
Please help i will give brainliest!!! thank you =)
Anastasy [175]

Answer:

Answer choice B. 2

Explanation:

7 0
3 years ago
CaO + H2O -> Ca(OH)2
yawa3891 [41]

The % yield of Ca(OH)₂ : 62.98%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

CaO + H₂O ⇒ Ca(OH)₂

mass CaO= 4.2 g

mol CaO(MW=56,0774 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{4.2}{56,0774 g/mol}\\\\mol=0.075

mol Ca(OH)₂ based on mol CaO

mol ratio CaO : Ca(OH)₂,= 1 : 1, so mol Ca(OH)₂ = 0.075

mass Ca(OH)₂(MW=74,093 g/mol) ⇒ theoretical

\tt mass=mol\times MW\\\\mass=0.075\times 74,093 g/mol\\\\mass=5.557~g

% yield :

\tt =\dfrac{actual}{theoretical}\times 100\%\\\\=\dfrac{3.5}{5.557}\times 100\%\\\\=62.98\%

8 0
3 years ago
The average adult heart pumps about 84. mL/s of blood at 72 beats per minute. Suppose you need to calculate how long it would ta
s2008m [1.1K]

Answer:

63.1 seconds.

Explanation:

Hello!

In this case, since the average adult heart pumps 84.0 mL/s of blood, it means 84.0 mL each second, as we have 5300. mL, the following mathematical set up help us to compute the required time:

t=5300.mL*\frac{1s}{84.mL}\\\\t=63.1s

Which is about 1.05 min.

Best regards!

3 0
3 years ago
The mole fraction of NaCl in an
AlekseyPX

Answer:

Moles of water are 0.868

Explanation:

7 0
3 years ago
What is the mole fraction of cation in 1M of aluminium sulphate​
Svetllana [295]

The mole fraction of cation (Al)=0.4

<h3>Further explanation</h3>

Given

1 M of Aluminium sulphate​

Required

The mole fraction of cation

Solution

Ionization of the Aluminum sulfate solution( assume 1 L solution ) :

mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol

Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻

1 mol          2 mol   3 mol

From this equation, total mol in solution = 2+3 = 5 moles

Mol fraction Al(as a cation) :

= 2/5=0.4

8 0
3 years ago
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